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nasty-shy [4]
3 years ago
5

There are 20 children at a library. Six of the children have an average age of 5 years. The remaining children have an average a

ge of 8 years. What is the average age of the children at the library? Enter your answer in the box. WILL GIVE BARINLIYEST
Mathematics
1 answer:
Allushta [10]3 years ago
7 0
Answer: The average age is 7.1 years.

This problem is an example of when we need to take a weighted average. We simply can't just find the average of 5 and 8, because there are different children of each each.

To start, lets multiply the total number of children by their individual ages.

6 x 5 = 30 years
14 x 8 = 112 years

There are 142 years among the 20 years, so divide 142 by 20. This gives us an average age of 7.1 years.
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Answer:

x= -7

Step-by-step explanation:

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3 years ago
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A circular table top has a radius of 60cm. A force of 650N is applied to the whole table top. Calculate the pressure in N/m to 4
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Answer:

i hope its understood....

8 0
3 years ago
Select the lesser of The two given numbers -152, 12
Ymorist [56]

Answer:

-152

Step-by-step explanation:

-152 < 12

-152 is negative, which means it is less than 1.

12 is positive, which means it is greater than 1.

Therefore, -152 is the lesser of the two given numbers.

Have a great rest of your day! :)

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2 years ago
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Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. the length of the yard is 10 feet
Anna35 [415]
Let x be the yard length, then if <span>the length of the yard is 10 feet more than 2 times the width, the length of the yard is 2x+10. The perimeter is 2 lengths + 2 widths, so P=2x+2(2x+10) .
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Since Sally <span>needs 56 feet of fencing to do the job, P=56 ft. and
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<span>2x+2(2x+10)=56,
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</span><span>2x+4x+20=56,
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3 years ago
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Use the raw data below to create a table that can be used to create a histogram with 5
schepotkina [342]

Answer:

Five classes

Step-by-step explanation:

1. Sort the data

You get

1.1, 1.3, 1.6, 1.7, 2, 2.6, 2.7, 2.9, 3.2, 3.2, 3.5, 3.5, 3.9, 4.6, 4.7, 4.8, 4.8, 4.9, 4.9, 5.3, 5.7, 6.4, 6.5, 7.1, 7.5, 7.6, 8.1, 8.2, 9.2, 9.4

2. Calculate the range

Range = Max - Min = 9.4 - 1.1 = 8.3

3. Calculate the class width

Divide the range by the number of classes

8.3/5 = 1.7

Round this up to 2.

4. Decide where to start the histogram

You could use classes: 1 - 3, 3 - 5, 5 - 7, 7 - 9, 9 -11

However, even numbers are easier to read.

It would be preferable to use classes: 0 - 2, 2 - 4, 4 - 6, 6 - 8, 8 - 10

5. Prepare a frequency distribution table

Note: Each class does not include its largest possible value. Thus, a value of 2 goes into Class 2 - 4, (not Class 0 - 2).

\begin{array}{cc}\textbf{Miles run} & \textbf{No. of students} \\0 - 2 & 4 \\2 - 4 & 9 \\4 - 6 & 8 \\6 - 8 & 5 \\8 - 10 & 4 \\\end{array}

4 0
3 years ago
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