A black-tailed jackrabbit hops about 7 feet in a single hop how far can a hop in 5 seconds
2 answers:
Answer:
A black-tailed jackrabbit can hopes 36 in 5 seconds.
Step-by-step explanation:
Consider the provided information.
Black tailed jackrabbit hopes 51 feet in one second.
Therefore, in 5 second Black tailed jackrabbit covers a distance of:
51×5=255 feet
So, in 5 seconds a black-tailed jackrabbit will travel 255 feet.
In one hops Black tailed jackrabbit covers 7 feet.
Now find the number of hops, we need to divide the distance by the length of one hop:
Hence, A black-tailed jackrabbit can hopes 36 in 5 seconds.
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Answer:
9.2
Step-by-step explanation:
You want the distance between A(2, 0) and B(0, 9).
<h3>Distance</h3>The distance formula is based on the Pythagorean theorem. It tells you the distance between (x1, y1) and (x2, y2) is ...
d = √((x2 -x1)² +(y2 -y1)²)
For the given points, this becomes ...
d = √((0 -2)² +(9 -0)²) = √(4+81) = √85
d ≈ 9.2
The distance between A and B is about 9.2 units.
We can use the arc length formula to solve this.
Arc length =
Given arc length is 7 and radius is 5, we can plug in the values and solve for q.
ANSWER:
We can use the equation to find the value of q. And, the value of q is 80.21°.