A black-tailed jackrabbit hops about 7 feet in a single hop how far can a hop in 5 seconds
2 answers:
Answer:
A black-tailed jackrabbit can hopes 36 in 5 seconds.
Step-by-step explanation:
Consider the provided information.
Black tailed jackrabbit hopes 51 feet in one second.
Therefore, in 5 second Black tailed jackrabbit covers a distance of:
51×5=255 feet
So, in 5 seconds a black-tailed jackrabbit will travel 255 feet.
In one hops Black tailed jackrabbit covers 7 feet.
Now find the number of hops, we need to divide the distance by the length of one hop:
Hence, A black-tailed jackrabbit can hopes 36 in 5 seconds.
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Step 1:
first let us convert the two decimals into fractions.
0.36=36/100 (since there are two digits after decimal point we divide by 100)
2.4=24/10 (since there are one digit after decimal point we divide by 10)
now we can multiply the fractions
×
multiplying numerator with numerator and denominator with denominator:
=
Now we can convert this back to decimal
864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.
Answer=0.864