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AlladinOne [14]
3 years ago
12

PLEASE HELP WILL MARK BRAINLIEST

Mathematics
2 answers:
Georgia [21]3 years ago
4 0
The answer clearly shows they both started with equal expressions.

Gennadij [26K]3 years ago
4 0

Answer:

Yes, they started with equal expressions.

Step-by-step explanation:

To simplify Vanessa's expression, we must rationalize the denominator.  This means we must make the denominator x.  We have

\frac{x^{\frac{4}{3}}}{x^{\frac{5}{6}}}

We need to multiply the denominator by x^(1/6) to make a whole x; this means we must multiply the numerator by x^(1/6) as well:

\frac{x^{\frac{4}{3}}}{x^{\frac{5}{6}}} \times \frac{x^{\frac{1}{6}}}{x^{\frac{1}{6}}}}\\\\=\frac{x^{\frac{4}{3}+\frac{1}{6}}}{x^{\frac{5}{6}+\frac{1}{6}}}\\\\=\frac{x^{\frac{8}{6}+\frac{1}{6}}}{x^\frac{6}{6}}}\\\\=\frac{x^{\frac{9}{6}}}{x}

Now we can separate the x^(9/6) in the numerator:

\frac{x^{\frac{9}{6}}}{x}\\\\=\frac{x^{\frac{6}{6}+\frac{3}{6}}}{x}\\\\=\frac{x^{\frac{6}{6}}(x^{\frac{3}{6}})}{x}\\\\=\frac{x(x^{\frac{3}{6}})}{x}\\\\=x^{\frac{3}{6}}=x^{\frac{1}{2}}=\sqrt{x}

William's expression is

(x\times x^3 \times x^4)^{\frac{1}{16}}\\

We first use the product property to simplify inside parentheses:

(x^{1+3+4})^{\frac{1}{16}}\\\\(x^8)^{\frac{1}{16}}

Now we use the product of a product property to multiply the exponents:

(x^8)^{\frac{1}{16}}\\\\=x^{\frac{8}{16}}\\\\=x^{\frac{1}{2}}=\sqrt{x}

Therefore they started with equal expressions.

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