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SVETLANKA909090 [29]
3 years ago
6

G(n)=3n^3-5 h(n)=2n-5 find(g+h)(2)

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

g(n) = 3n³ - 5           h(n) = 2n - 5              (g + h)(2) = g(2) + h(2)

g(2) = 3(2)³ - 5  = 3(8) - 5   = 24 - 5   = 19

h(2) = 2(2) - 5   = 4 - 5   = -1

g(2) + h(2) = 19 + -1   = 19 - 1   = 18

Answer: 18

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Answer:

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Step-by-step explanation:

we are given a series

Firstly, we will find nth term

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Denominator:

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so, nth term will be

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so, we can find it's nth term as

c_n=\frac{n+3}{n+4}

we can use divergent test

\lim_{n \to \infty}  c_n=\lim_{n \to \infty} \frac{n+3}{n+4}

we can divide top and bottom by n

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}

now, we can plug n=inf

\lim_{n \to \infty}  c_n= \frac{1+0}{1+0}

\lim_{n \to \infty}  c_n=1

Since, it is non-zero value

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Step-by-step explanation:

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