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GrogVix [38]
3 years ago
15

Given the incomplete equation representing a reaction:

Chemistry
1 answer:
Akimi4 [234]3 years ago
3 0
O is what should go in the blank. O stands for Oxygen.
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PLS ANSWER ASAP, WILL GIVE BRAINLIEST ANSWER
Stolb23 [73]

Answer:

.14L or 140mL

Explanation:

This is a classic plug-n-chug problem. Your textbook probably goes over this formula as M_{1}V_{1} = M_{2}V_{2}. M stands for molarity of the given substance, and V stands for the volume that the substance occupies.

Simply plug in the values that you're given, like so:

M_{1} = 1.5M\\V_{1} = ???\\M_2 = 7M\\V_2 = .03L

1.5M * x = 7M * .03L

After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.

6 0
3 years ago
Is air an element, compound or mixture? explain your answer
emmainna [20.7K]

It is a mixture because the compounds that make up air e.g. oxygen (o2), Carbon dioxide (co2) and the most important Nitrogen which is an element and makes up 78.09% of air are not chemically bound in the way that compounds are because they can be separated easily and there has been no change in state to any of the compounds or elements in air!hope this helpful!

3 0
4 years ago
Read 2 more answers
This body system is where oxygen gas and carbon dioxide gas are exchanged in our body. *
nexus9112 [7]

Answer:

The answer is the respiratory system

Explanation:

The function of the respiratory system is to move two gases. These two gases are called oxygen and carbon dioxide. Gas exchange takes place in the millions of alveoli in the lungs and the capillaries that envelop them.

6 0
4 years ago
Read 2 more answers
Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?
Mariulka [41]
  • Volume=V=3L
  • Pressure=P=814mmHg
  • Temp=T=25°C

So

No of moles=n

\\ \rm\rightarrowtail PV=nRT

\\ \rm\rightarrowtail n=\dfrac{PV}{RT}

\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}

\\ \rm\rightarrowtail n=2442/25R

\\ \rm\rightarrowtail n=97.7Rmol

5 0
2 years ago
How many kilocalories are required to increase the temperature of 15.6 g of iron from 122 °c to 355 °c. the specific heat of iro
Dmitriy789 [7]

Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

Q = m s dT

Where, m is mass of iron

s is specific heat of iron

d T is change in temperature in celcius

= 15.6 g * 0.45 J /g /C * (355 - 122)  = 1.63 * 10^3 J

If  

1 cal = 4.2 J

Then,  

Q = (1.63 * 10^3) /4.2 = 0.389 K cal

Thus 0.389 k cal of enrgy  is required by a 15.6 g Fe to reach to 355 C^0

4 0
4 years ago
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