Answer:
Answer is D.it gains and loses electrons.
Explanation:
I hope it's helpful!
We need to find the Ka value of HF. First, set up the balanced chemical equation:
HF ===> H+ + F-
The formula for the Ka value of an acid is
Ka = [concentration of products] / [concentration of reactants]
Ka = [H+] [F-} / [HF]
So if we are given the concentration of the products and reactants, we will be able to solve for the Ka value of HF.
<span>N2</span>+3<span>H2</span>→2N<span>H<span>3 hope this helps
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a) (NH4)2SO4 --- 1 mole of it contains 2 moles of N, 8 moles of H, 1 mole of S, and 4 moles of O.
MM = (2 moles N x 14.0 g/mole) + (8 moles H x 1.01 g/mole) + (1 mole S x 32.1 g/mole) + (4 moles O x 16.0 g/mole) = 132 g/mole.
6.60 g (NH4)2SO4 x (1 mole (NH4)2SO4 / 132 g (NH4)2SO4) = 0.0500 moles (NH4)2SO4
b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.
4.5 kg Ca(OH)2 x (1000 g / 1 kg) x (1 mole Ca(OH)2 / 74.0 g Ca(OH)2) = 60.8 moles Ca(OH)2
