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Lelu [443]
3 years ago
9

A student dissolved 3.50g of copper (II) nitrate in water and mixed it with a solution of sodium carbonate. The student recovere

d 1.89g of copper carbonate precipitate. If the theoretical yield is 2.35g, what is the percent yield
Chemistry
1 answer:
Arisa [49]3 years ago
3 0

Answer: If the theoretical yield is 2.35g then the percent yield is 80.4%

Explanation:

Given: Actual yield = 1.89 g

Theoretical yield = 2.35 g

Formula used to calculate the percentage yield is as follows.

Percent yield = \frac{actual yield}{theoretical yield} \times 100

Substitute the values into above formula as follows.

Percent yield = \frac{actual yield}{theoretical yield} \times 100\\= \frac{1.89}{2.35} \times 100\\= 80.4 percent

Thus, we can conclude that if the theoretical yield is 2.35g then the percent yield is 80.4%

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Explanation :

Formula used :

q=m\times c\times (T_2-T_1)

where,

q = heat needed = ?

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T_1 = initial temperature = 20.0^oC

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Now put all the given values in the above formula, we get:

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