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ValentinkaMS [17]
3 years ago
6

The Two questions below is that I need help with. I need to break apart the numbers into tens and ones

Mathematics
1 answer:
Aleks [24]3 years ago
7 0
First Problem:

44 + 57 = 101

10 + 10 + 10 + 14 

10 + 10 + 10 + 10 + 17 = 101

Second Problem: 

25 + 64 = 89

10 + 10 + 5

10 + 10 + 10 + 10 + 10 + 14 = 89

Hope this helps. :)

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Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin
Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0
4 years ago
The temperature at 6pm was 0 degrees Fahrenheit at 10 pm the temperature was -11.2 degrees Fahrenheit write an expression that y
lana66690 [7]
The answer is the temperature goes down 2.8° every hour and the expression is x=-11.2/4 because 4 is how many hours between 6pm and 10pm and its -11.2 because that was how much the temperature dropped from 6pm to 10pm
8 0
3 years ago
(( I will give 25 points and brainy from right answers (Please answer all!!) )
sleet_krkn [62]
1. C. Concave pentagon

2. A. 1620°

b/c (11 - 2) × 180 = 1620

3. B. 165°

b/c (24 - 2) × 180 ÷ 24 = 165

4. A. 160°

b/c (18 - 2) × 180 ÷ 18 = 160
6 0
3 years ago
{1, -2),(-2, 0),(-1, 2),(1, 3)}<br> Function
Over [174]

Answer:

this is a function

Step-by-step explanation:

the x does not repeat itself

7 0
3 years ago
4. 9d - 5 = 4<br><br> What does d =<br> 5. 6-3w=-27 what does w =<br> 6. -4= q/8-19 what does q =
trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

<em>4)</em> 9d - 5 = 4

Adding 5 on both the sides ,

=  > 9d - 5 + 5 = 4 + 5

=  > 9d = 9

Dividing both the sides by 9 ,

=  >  \frac{9d}{9}  =  \frac{9}{9}

=  > d = 1

<em>5)</em> 6 - 3w =  - 27

Substracting 6 from both the sides ,

6  - 3w - 6 =  - 27 - 6

=  >  - 3w =  - 33

Dividing both the sides by -3 ,

=  >  \frac{ - 3w}{ - 3}  =  \frac{ - 33}{ - 3}

=  > w = 11

<em>6)</em> - 4 =  \frac{q}{8}  - 19

Adding 19 on both the sides ,

\frac{q}{8}  - 19 + 19 = - 4 + 19

=  >  \frac{q}{8}  = 15

Multiplying both the sides by 8 ,

=  >  \frac{q}{8}  \times 8 = 15 \times 8

=  > q = 120

6 0
3 years ago
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