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bagirrra123 [75]
3 years ago
12

Sound waves are also called compression waves. This means that as the wave travels through air, the ________ increases and decre

ases.
motion


light


pressure


energy
Physics
1 answer:
Nuetrik [128]3 years ago
3 0
I believe the answer is pressure. hope this helps
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The shape is square pyramidal based on an oc- tahedral arrangement of electrons about the Xe atom

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7 0
3 years ago
What is one result of a chemical change?
nordsb [41]
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7 0
3 years ago
if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
An ultracentrifuge accelerates from rest to 99300 rpm in 1.95 min. Randomized Variables f = 99300 rpm t = 1.95 min l = 9.4 cm
Levart [38]

Answer: i'm pretty sure its part B

7 0
4 years ago
the speed of a train is decreased in a uniform rate from 96 km/h to 48km/h through a distance of 800m. calculate the distance co
GREYUIT [131]

Answer:

1066.67 m

Explanation:

Given:

v₀ = 96 km/h = 26.67 m/s

v = 48 km/h = 13.33 m/s

Δx = 800 m

Find: a

v² = v₀² + 2aΔx

(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)

a = -0.333 m/s²

Given:

v₀ = 26.67 m/s

v = 0 m/s

a = -0.333 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx

Δx = 1066.67 m

Round as needed.

7 0
3 years ago
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