Type of image is either real or virtual.
Real images (convex)
-light rays travel to a real image from the object
Virtual images (concave)
-not really there and no light reaches them
d. type of light source
**just an opinion, i might be incorrect
Work = (Force) * (Displacement). Force = 10 newtons Distance or Displacement 5 meters. Therefore,the Work done = (10 newtons * 5 meters) = 50 joules. The Answer is 50 Joules of Force
Below are the answers:
a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page at<span>the bottom
</span>V=-Δφ/ Δt = -B·ΔA/ Δ<span>t
b. </span>As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radially<span>outward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law
</span>F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvB<span>ˆ
</span>Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because the<span>force is pointing into the center of the loop, we know we have positive current at that point (into the page).</span>
Answer:
Distance-time graphs. If an object moves along a straight line, the distance travelled can be represented by a distance-time graph.
Explanation:
Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.
where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
![P=1027*9.81*6.25\\P=62967.93[Pa]](https://tex.z-dn.net/?f=P%3D1027%2A9.81%2A6.25%5C%5CP%3D62967.93%5BPa%5D)
The net force is:
![F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]](https://tex.z-dn.net/?f=F%20%3D%20P%2AA%5C%5CF%20%3D%2062967.93%2A0.00849%5C%5CF%20%3D%20534.6%5BN%5D)
