Ask question

Ask question

All categories

4 years ago

9

What is 1 and 1/4 minus 5/12

2 answers:

lara [203]4 years ago

8 0

5/6! Because....1 1/4 can be converted to 5/4 so then the equation would be 5/4-5/12 but when your subtracting the numbers HAVE to have the same denominator and the LCM of 4 and 12 is 12 so then the equation would be 15/12 (because when you change the denominator you also have to multiply the LCM divided by the number which would be 3 times 5) so anyyywwwaaaayyy the equation would be 15/12-5/12=10/12 which can be simplified to 5/6!!!!!!!!! And there u have it!

SSSSS [86.1K]4 years ago

3 0

One and one-fourth equals to 5 over 4
5/4 times 3/3 equals to 15/12
subtract 5/12 from 15/12
the answer is 10/12
simplest form is 5/6
hope it helped
hit the brainiest button!

You might be interested in

(HELO FAST )What is the solution to this system of equations? *

Alex787 [66]

Answer:

A

Step-by-step explanation:

i think thats the answer

8 0

3 years ago

Read 2 more answers

What is the value of x

bulgar [2K]

x equals negative 8 that's it

5 0

4 years ago

Read 2 more answers

The points (4,7) and (r. – 5) lie on a line with slope – 3. Find the missing coordinate r

dusya [7]

Answer:

$r=\frac{14}{3}$

Step-by-step explanation:

Set up an equation and solve for r using the formula for slope:

$\frac{5-7}{r-4}=-3\\ \\-2=-3(r-4)\\\\-2=-3r+12\\\\-14=-3r\\\\\frac{14}{3}=r$

7 0

2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago

Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)

Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

$m =\frac{y_{2}-y_{1} }{x_{2} -x_{1} } =\frac{-7-5}{2-(-1)} = \frac{-12}{3} = -4$

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

$y - y_{1} = m( x-x_{1} )$

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em> </em></u>

6 0

3 years ago