The rewritten form of the expression given in the task content in which case, the properties of the logarithm are used is; log2(z³/y²) + log9(y⁴x¹²).
<h3>What is the equivalent expression to the logarithmic expression given in the task content?</h3>
It follows from the task content that the logarithmic expression given in the task content is;
log2z + 2log2z + 4log9y + 12log9x - 2log2y
In which case, all terms are to their respective logarithmic bases.
Hence, it follows that; we have;
log2z³ - log2y² + log9y⁴ + log9x¹²
= log2(z³/y²) + log9(y⁴x¹²)
Read more on logarithm laws;
brainly.com/question/10208274
#SPJ1
"31-inch piece of steel is cut into three pieces"
Call the pieces a,b,c
a + b + c = 31
"second piece is twice as long as the first piece"
b = 2a
"third piece is one inch more than seven times the length of the first piece"
c = 1 + 7a
Ok, we have our equations, let's substitute the second and third into the first.
a + 2a + 1 + 7a = 31
10a + 1 = 31
10a = 30
a = 30/10 = 3
b = 2a = 6
c = 1 + 7a = 22
Check: 3 + 6 + 22 = 31, good
Answer: 3 inches, 6 inches, 22 inches
Answer:
a) (59180,60820)
b) (59020,60980)
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $60,000
Standard Deviation, σ = $5,000
Sample size, n = 100
a) 90% critical values
Putting the values, we get,

b) 95% critical values
Putting the values, we get,

To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.