Question

I am stuck on this one.

Answer 1

Answer: $-\frac{\sqrt{3} }{3}$

Step-by-step explanation:

Tan is $\frac{sin}{cos}$

sin is the y coordinate

Cos is the x-coordinate

$\ \frac{11\pi }{6} = (\frac{\sqrt{3} }{2} ,-\frac{1}{2})$

$tan=\frac{\frac{1}{2} }{\frac{\sqrt{3} }{2} }$

$-\frac{1}{2} *\frac{2}{\sqrt{3} } =- \frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =-\frac{\sqrt{3} }{3}$

Answer 2

Answer: A. Is the answer for sure!!!

Explanation: have a good day!