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Leviafan [203]
3 years ago
6

The flight path of a plane is a straight line from city J J to city K K. The roads from city J J to city K K take the long way a

round, traveling 9.4 9.4 miles south and then 15.1 15.1 miles east. How many degrees east of south is the plane's flight path, to the nearest tenth? M ∠ J ≈ ? M∠J≈
Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

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If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
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Answer:

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To find (h-g) (-2) we must first find h - g(x)

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To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

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We have the final answer as

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Hope this helps you

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Answer:

5

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Read 2 more answers
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