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Leviafan [203]
3 years ago
6

The flight path of a plane is a straight line from city J J to city K K. The roads from city J J to city K K take the long way a

round, traveling 9.4 9.4 miles south and then 15.1 15.1 miles east. How many degrees east of south is the plane's flight path, to the nearest tenth? M ∠ J ≈ ? M∠J≈
Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

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Answer:measurement of angle B is

70 \:  \: degrees

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3 years ago
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Answer:

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Step-by-step explanation:

Use the formula: d = vi t + \frac{1}{2} at^{2}

d = distance      vi = initial velocity (m/s)    

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m is meters and s is seconds. They are units of measurement so leave them be.

Assuming the object is simply dropped, the initial velocity is 0 since the object was not moving before it was dropped.

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The acceleration is 9.81m/s^{2} since that is the acceleration of Earth's gravity, aka free fall.

Time is what we are trying to find so just leave it as the variable t.

So plug the values into the equation:

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Remember to pay attention to units because your answer will be wrong otherwise

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