Question

Simplify this please (m×n)^-1=

Answer 1

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\ -------------------------------\\\\ (m\times n)^{-1}\implies \cfrac{1}{(m\times n)^1}\implies \cfrac{1}{mn}$

Answer 2

We can solve this by using the exponent rule $a^{-n} = \frac{1}{a^{n} }$. In this case, a is mn and -n is -1. That means that the simplified version of this is $\frac{1}{(mn)^{1} }$ = $\frac{1}{(mn)}$ (anything to the power of one is itself).