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Anvisha [2.4K]
3 years ago
7

It has been determined that the number of fish f(t) that can be caught in t minutes in a certain pond using a certain bait is f(

t) = .25t + 1, for t > 10. Find the number of fish that can be caught if you fish for 15 minutes. Round your answer to the nearest whole number.

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
It has been determined that the number of fish f(t) that can be caught in t minutes in a certain pond using a certain bait is f(t) = .25t + 1, for t > 10. Find the number of fish that can be caught if you fish for 15 minutes. Round your answer to the nearest whole number.

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(3p+5)(2) simplified
Vsevolod [243]
Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10
8 0
2 years ago
Please help me please
GarryVolchara [31]

Answer:

4. false 1 is nor prime nor composite

3 0
1 year ago
Determine if the expression - 4x²/2 is a polynomial or not. If it is a polynomial,
9966 [12]

Answer:

Step-by-step explanation:

Yes this is a  polynomial.

Type - monomial

Degree = 2              {Highest power of the variable is the degree}

8 0
3 years ago
20 POINTS
amid [387]
So first thing you need to understand is that ABC and AFE are congruent triangles. This means we can find the other angles, based on ABC:

Angle FAE = 26.56505118 degrees
Angle AEF = 63.43494882 degrees

Angles ECD and DEC are both 45 degrees

Now, we can find the angles in ACE:

AEC = 71.56505118 degrees
ECA = 71.56505118 degrees
CAE = 36.86989764 degrees
7 0
3 years ago
- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level
alina1380 [7]

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

H_0: \mu = 85

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

H_1: \mu < 85

<h3>What is the decision?</h3>

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918

5 0
2 years ago
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