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Anvisha [2.4K]
3 years ago
7

It has been determined that the number of fish f(t) that can be caught in t minutes in a certain pond using a certain bait is f(

t) = .25t + 1, for t > 10. Find the number of fish that can be caught if you fish for 15 minutes. Round your answer to the nearest whole number.

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
It has been determined that the number of fish f(t) that can be caught in t minutes in a certain pond using a certain bait is f(t) = .25t + 1, for t > 10. Find the number of fish that can be caught if you fish for 15 minutes. Round your answer to the nearest whole number.

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HELP PLEASEEEE ITS DUE SOON! SHOW YOUR WORK & ILL GIVE BRAINLIEST I PROMISE
laiz [17]

Answer:

(2,10) or x=2 y=10

Step-by-step explanation:

<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>

5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)

5x=2y-10 (Divide the 5 from the x)

x=2/5y-2

<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>

3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)

6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)

36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)

y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)

y=10

<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>

5x-2(10)=-10 (Multiple 2 by 10)

5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)

5x=10 ( Divide 10 by 5)

x= 2

<em>4. If needed, plug in the values of x and y to check your solution.</em>

Hope this could help! :)

3 0
2 years ago
Find the x and y intercept of 8x+10y=15. NO LINK TO ANSWER PLEASE TYPE
oee [108]

Answer:

x intercept: 15/8 and yintercerpt is 3/2

Step-by-step explanation:

to find y intercept you have to put equation in standard form.

10y=-8x+15

y=--4/5x+3/2

x intercept is when y=0, so we plug in 0

0=-4/5x+3/2

4/5x=3/2

x=15/8

7 0
2 years ago
which of the following properties could be used to rewrite the expression (2/3•1/5)•5/2 as 2/3•(5/2•(5/2•1/5) sorry to ask Su ma
slamgirl [31]
The original expression is given by:
 ( \frac{2}{3}*\frac{1}{5})*\frac{5}{2}
 The correct way to rewrite the expression is given by:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})&#10;
 For this, we use two properties:

 Associative property:
 The way of grouping the factors does not change the result of the multiplication:
 \frac{2}{3}*(\frac{1}{5}*\frac{5}{2})

 Commutative property:
 
The order of the factors does not vary the product:
 \frac{2}{3}*(\frac{5}{2}*\frac{1}{5})
8 0
3 years ago
the ratio of the length of shantels pool to the length of juan's pool is 3 to 5 shantels pool is 30 meters how long is Juan’s po
love history [14]

Step-by-step explanation:

the ratio of the pool lengths is 3/5.

that means for every 3 meters of length on Shantel's pool, there are 5 meters of length on Juan's pool.

it the other way around : to get to the size of Shantel's pool, every 5 meters of length on Juan's pool are converted to 3 meters.

x = length of Juan's pool

x × 3/5 = 30

3x = 150

x = 50 meters

you see the relationship ?

3/5 = 30/50 = 300/500 = ...

but it is true for any factor

3/5 = 15/25 = 24/40 = 6/10 = ...

once you see the factor for one part of the ratio, you know there is the same factor for the other part (or parts) of the ratio. otherwise the ratio would not stay the same and keep the relationship.

3 0
2 years ago
Find the HCF and LCM of the following pairs of numbers:
Marina86 [1]

Answer:

a)HCF between 774&252 is=18

LCM between 774&252=10836

b)HCF between 204&544 is=68

LCM between 204&544 is=1632

c)HCF between 770&385 is=385

LCM between 770&385 is =770

d)HCF between 477&552=3

LCM between 447&552 is =82248

Step-by-step explanation:

a)because LCM=2×2×3×3×7×43

b)because LCM=2×2×2×2×2×3×17

c)because LCM=2×5×7×11

d)because LCM=2×2×2×3×23×149

4 0
2 years ago
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