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Elina [12.6K]
3 years ago
5

Magnetic reversals have helped to support

Physics
1 answer:
sveticcg [70]3 years ago
5 0


Magnetic reversals have helped support the theory of sea floor spreading, that Harry Hess, professor of geology had put forth. He proposed that the ocean progressively widens as new sea floor is created along a crack that follows the crest of ridges found in the middle of the ocean.

In 1963, Fred Vine, Drummond Mathews and others found that the crust surrounding the mid-ocean ridges showed alternating bands, each band magnetized with a polarity opposite the surrounding bands. They suggested that as new sea-floor crust was formed around the crack or rift in the mid-ocean ridge, it magnetized differently depending upon the polarity of the planet at that time, supporting the theory of Harry Hess.  


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Complete Question

Which phenomena support only the wave theory of light? Check all that apply.

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Solution

There are two theories/schools of thoughts that light possesses wave and particle properties.

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Properties that support the wave properties of light are diffraction (ability to navigate or bend around obstacles) and Interference (two light waves can combine or superimpose to form a single resultant light wave with amplitude greater, lower or equal to the amplitudes of the two constituting light waves).

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<h3>What is magnetic field strength?</h3>

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

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B = \frac{\mu_0I}{2r}  \\\\ \mu_0 = 4 \PI \times 10^{-7}

In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.

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\rm B_{net} = B1_+(-B_2)

B = \frac{ 4 \PI \times 10^{-7}I}{2r}  \\\\  \rm B_{net} = B_1_+(-B_2)\\\\ \rm B_{net} = \frac{4 \times \pi \times 10^{-7} \times 10}{2 \times \pi \times 0.02} -\frac{4 \times \pi \times 10^{-7} \times 10 }{2 \times \pi \times 0.06} \\\\\  \rm B_{net} = 6.67 \times 10^{-5} T

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