Answer:
25.59 m/s²
Explanation:
Using the formula for the force of static friction:
--- (1)
where;
static friction force
coefficient of static friction
N = normal force
Also, recall that:
F = mass × acceleration
Similarly, N = mg
here, due to min. acceleration of the car;
From equation (1)
However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.
Thus,
where;
and g = 9.8 m/s²
Answer:
twice the original speed
Explanation:
the centripetal force is the force of an object moving in a circle of turning and it is given by the expression
where f = force of the object
m = mass
v = velocity
r = radius of the circle
first we need to know what the orignal speed will be then we can tell what will happen if the radius of the circle is changed to 4R.
from the expression for the centripetal force, we need to make the velocity subject of the formula
now, if the radius is changed to 4R
in the expression for v above i will need to just insert 4R in place of r
the square root of 4 is 2,
therefore
we can see that this is just twice of what the original speed was.