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suter [353]
3 years ago
11

If a moving car speeds up until it is going twice as fast, how much kinetic energy doe s it have compared with its initial kinet

ic enegy
Physics
1 answer:
dezoksy [38]3 years ago
6 0
The kinetic energy of an object of mass m and velocity v is given by
K= \frac{1}{2} mv^2

Let's call v_i the initial speed of the car, so that its initial kinetic energy is
K_i =  \frac{1}{2} mv_i^2
where m is the mass of the car. 

The problem says that the car speeds up until its velocity is twice the original one, so 
v_f = 2 v_i
and by using the new velocity we can calculate the final kinetic energy of the car
K_f =  \frac{1}{2} mv_f^2 =  \frac{1}{2}m (2 v_i)^2 = 4 ( \frac{1}{2} mv_i^2)=4 K_i
so, if the velocity of the car is doubled, the new kinetic energy is 4 times the initial kinetic energy.
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Woman has a near point of 75.0 cm. What focal length, f, is necessary for the corrective lens so that he can hold his physics bo
Komok [63]

Answer:

The focal length of the lens must be 27.3cm

Explanation:

Image distance= -75 cm

Object distance= 20.0cm

From:

1/v + 1/u = 1/f

-1/75+ 1/20 = 1/f

11/300= 1/f

f= 300/11

f= 27.3cm

The focal length of the lens must be 27.3cm

8 0
3 years ago
If you throw an apple towards the sky why its going up in spite of gravitational pull?
AlexFokin [52]

Answer:

Force

Explanation:

The Force You Put Behind Said Apple Is Greater Than That Of Gravitational Pull

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6 0
2 years ago
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The distance from the Earth to the Sun equals 1 AU. Neptune is 30 AU from the Sun. How far is Neptune from the Earth? AU
valina [46]

Answer:

The answer is 29 AU

Hoped I helped

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4 0
3 years ago
Read 2 more answers
According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
ohaa [14]

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, <u>the attraction or repulsion becomes weaker</u>, decreasing to one-fourth of the original value.

Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

F is the force.

k is the Coulomb's constant (8.987*10^{9} \frac{Nm^{2} }{C^{2} }).

q_{1} is the electric charge of object 1.

q_{2} is the electric charge of object 2.

r is the distance between the two charges.

Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

8 0
2 years ago
A projectile is fired with an initial velocity of 450 feet per second at an angle of 70° with the horizontal.
pav-90 [236]
<h2>After 26.28 seconds projectile returns 26.28 seconds.</h2>

Explanation:

Initial velocity = 450 ft/s = 137.16 m/s

Angle, θ = 70°

Consider the vertical motion of projectile,

When the projectile return to the ground we have

           Displacement, s = 0 m

           Acceleration, a = -9.81 m/s²

            Initial velocity, u = 137.16 x sin70 = 128.89 m/s

Substituting in s = ut + 0.5 at²

                s = ut + 0.5 at²

                0 = 128.89 x t + 0.5 x (-9.81) x t²

                t² - 26.28 t = 0

                t ( t- 26.28) = 0

               t = 0 s or t = 26.28 s

After 26.28 seconds projectile returns 26.28 seconds.

5 0
3 years ago
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