Question

A 1 cm2 silicon solar cell has a saturation current of 10A and is illuminated with sunlight yielding a short-circuit photocurrent of 25 mA. Calculate the solar cell efficiency and fill factor.

Answer 1

Answer:

The answer is "13% and 83%"

Explanation:

The highest power is generated for:

$\to \frac{dP}{dV_a}=0= I_s(e^{\frac{V_m}{V_t}} -1)-I_{Ph} +\frac{V_m}{V_t} I_s e^{\frac{V_m}{V_t}}$

 Where voltage, $V_m$, was its calculated maximum power wattage.  This same following transcend national stable coins the power output:

$\to V_m=V_t \ In \frac{1+\frac{I_{ph}}{I_s}}{1+\frac{V_{m}}{V_t}}$

The accompanying consecutive values of $V_m$ are done utilizing iteration and an initial value of 0.5 V:

$\to V_m = 0.5,\ 0.542,\ 0.540 \ V$

Efficacy is equivalent to:

$\eta = |\frac{V_{m} I_{m}}{p_{in}}| =\frac{0.54 \times 0.024}{0.1}=1.3\%$

Currently, $I_m$ was calculated with the formula of voltage $V_m$ (4.6.1) as well as the sun is presumed to produce  $100 \frac{mW}{cm^2}$ of power.

The fulfillment factor is equal to:

fill factor$= \frac{V_{m} I_{m}}{V_{oc}I_{sc}}= \frac{0.54 \times 0.024}{0.62 \times 0.025}=83\%$

where open circuit tension of equations (4.6.1) and I = 0. is calculated. The current is equal to the total current of the photo.