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fomenos
3 years ago
9

Pentagon DEFGH is translated 4 units to the right to create pentagon UVXYZ. DE is 5cm long. What is the length of UV?

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
If a shape is translated (has it's vertex' coordinates moved/changed), then it retains its original values but just has different vertex coordinates.

Thus since DE is equal to UV, then,

DE = UV; substitution:
5=5
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A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is
miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n.  After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0
3 years ago
To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a
Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

The mean height is, <em>μ</em> = 100 meters.

The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})

                    =P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0
3 years ago
There are 120 boys in Morris middle school. What is the total number
AnnZ [28]

Answer:

121

Step-by-step explanation:

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8 0
3 years ago
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Jaida read 375 in 3 days how many pages does she read in one day
Genrish500 [490]

Answer:

<h2>She reads 125 pages each day.</h2>

Step-by-step explanation:

<h3>You just divide 375 by 3</h3><h3>hope this helps :)</h3>
4 0
3 years ago
Does anyone know how to do this
Doss [256]

Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

Step-by-step explanation:

Considering the quadrilateral with vertices

d(0,0)

i(5,5)

n(8,4)

g(7,1)

Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

From the figure a, it is clear that the quadrilateral has

Two pairs of sides

Each pair having two equal-length sides which are adjacent

The angles being equal where the two pairs meet

Diagonals as shown in dashed lines cross at right angles,  and one of the diagonals does bisect the other - cuts equally in half

Please check the attached figure a.

4 0
3 years ago
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