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Artist 52 [7]
3 years ago
14

12 1/4 - 5 2/3 subtract fraction with remaining

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
12 1/4 = 49/4
5 2/3 = 17/3

49/4 = 147/12
17/3 = 68/12

14/12 - 68/12 = 79/12
6 5/12
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Write the equation of the line perpendicular to
r-ruslan [8.4K]
Solving for y, we add 5y to both sides and subtract 4, getting 9x-4=5y. Dividing both sides by 5, we get 9x/5-4/5=y. Since the slope is 9/5 (since 9/5*x=9x/5), we multiply it by -1 and find the reciprocal of it to get -5/9 as the perpendicular slope, so -5x/9+b=y. Plugging 1 in for x and -6 in for y, we get -5*1/9+b=-6 and by adding 5/9 to both sides we get -5-4/9=b , and since in y=mx+b y and x are variables, we end up with y=-5x/9+(-5-4/9) for slope intercept form.

To get it into standard form, we need it in ay+cx=b with a, b, and c being constants. Adding 5x/9 to both sides, we end up with y+5x/9=(-5-4/9) for standard form


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3 years ago
Which equation is the slope intercept form of this equation?
AnnZ [28]

Answer:

C

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7 0
3 years ago
Diviseur de 63 et 67
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<span>Diviseur de 63 et 67</span>

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Read 2 more answers
Solve for the indicated variable 3x - y = 10; y
VashaNatasha [74]

Answer:

y = 3x - 10

Step-by-step explanation:

Starting with 3x - y = 10, add y to both sides:

3x = 10 + y

Then subtract 10 from both sides:

3x - 10 = y

If you switch the sides of the equation, it can also be written as:

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7 0
3 years ago
g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
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