As a matter of simplification, same/same = 1.
now, "same" could be anything whatsoever, you name it, a whole polynomial, a whole anything whatsoever.
![\bf \cfrac{\sqrt{2}}{\sqrt{2}}=\cfrac{\sqrt{3}}{\sqrt{3}}=\cfrac{100000000}{100000000}=\cfrac{eggs}{eggs}=\cfrac{miles}{miles}=\cfrac{\frac{\quad \sqrt{3}}{\sqrt[5]{17}}\quad }{\frac{\sqrt{3}}{\sqrt[5]{17}}}=\cfrac{whatever}{whatever}=1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%7B2%7D%7D%3D%5Ccfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%7D%3D%5Ccfrac%7B100000000%7D%7B100000000%7D%3D%5Ccfrac%7Beggs%7D%7Beggs%7D%3D%5Ccfrac%7Bmiles%7D%7Bmiles%7D%3D%5Ccfrac%7B%5Cfrac%7B%5Cquad%20%5Csqrt%7B3%7D%7D%7B%5Csqrt%5B5%5D%7B17%7D%7D%5Cquad%20%7D%7B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%5B5%5D%7B17%7D%7D%7D%3D%5Ccfrac%7Bwhatever%7D%7Bwhatever%7D%3D1)
now, that said, let us use 1 in this case then ... hmmmm we simply need a "y" in the denominator, so we simply multiply the denominator AND numerator by "y", y/y = 1 btw.
2x-4x
is an expression that equals too -4 if thats what u were looking for
Answer:
5/7 =55
5x/7 =55
7 ⋅ 5x/7 = 7 ⋅ 55
5x = 7⋅ 55
x= 77
1/5/6 = 6x/6
x= 1/30
x+ 2.17 = 5
x+ 2.17 = 5 - 2.17 = 5 - 2.17
x=2.83
Step-by-step explanation:
Answer:
x - 3y + z
Step-by-step explanation:
Terms are just names for objects inside the equation -- anything that isn't an operation. A coefficient the is the number a given term (variable) is being mulitpled by. In this case, -3 for y, and 1 for. x. We can deduce from this the start of the expression (x has no coeff. bc of multiplicative identity)
x - 3y
We know we are missing one term, and we also know that the third term cannot be constant, so it must be another variable. In this case I have chosen Z, in theory it shouldn't really matter but z is the best variable name in this case.
First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
