2 years ago

The midpoint of a line segment is (4, 2). If one of the endpoints is (-2, 3), what is the other endpoint?

Mathematics

1 answer:

stiks02 [169]2 years ago

3 0

I think it’d be (10, 1)

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user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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2 years ago

Find the distance between the points (13, 20) and (18, 8).<br> 13<br> 7<br> 11

Lana71 [14]

Answer: 13

Step-by-step explanation:

See attached graph.

A third point (18,20) may be added to the two given points to form a right triangle with sides 5 and 12. The distance, x, between the original two points is given by x^2 = 5^2 + 12^2

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