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Kay [80]
3 years ago
7

Which of the following is the graph of y= - x + 1

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

See picture below

Step-by-step explanation:

To graph properly, remember that:

  • The y intercept of the function, is the value of the function when x=0, and tells (in this case y=1 is the intercept). Locate this point in the graph.
  • The x intercept, which is the value of x when y=0 is x=1. Locate it in the graph.
  • You now have two points of a straight line: join this two points and you would have done it!

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Jesse buys a necklace that is on sale for 25% off the original price is 119.50 if tax is 7% what is the total price that Jesse w
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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
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\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill

\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6

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