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2 years ago

What are the first two lines of defense a company should take when addressing security risks?

Computers and Technology

1 answer:

Vsevolod [243]2 years ago

6 0

Answer:

People first, technology second

Explanation: A research work suggested that a greater focus on people, not just technology, gives functional managers control to acquire the best talent, develop the right skills, and keep employees engaged and feeling accountable for their work and how they impact your company's success. So people first and technology second is really a good idea, besides, the technologies were invented by people who chose to develop their skill(s).

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A combination lock has the following basic properties:

fomenos

Answer:

public class CombinationLock {

private int combinationNumber1 = 0;

private int combinationNumber2 = 0;

private int combinationNumber3 = 0;

CombinationLock(int combinationNumber1, int combinationNumber2, int combinationNumber3){

this.combinationNumber1 = combinationNumber1;

this.combinationNumber2 = combinationNumber2;

this.combinationNumber3 = combinationNumber3;

}

public boolean open(int number1, int number2, int number3){

if(number1 == combinationNumber1 && number2 == combinationNumber2 && number3 == combinationNumber3)

return true;

else

return false;

}

public boolean changeCombo(int number1, int number2, int number3, int newNumber1, int newNumber2, int newNumber3){

if (open(number1, number2, number3)){

combinationNumber1 = newNumber1;

combinationNumber2 = newNumber2;

combinationNumber3 = newNumber3;

return true;

}else

return false;

}

Explanation:

- <em>Three variables</em> are created to hold the combination.

- A <em>constructor</em> is created to set the combination.

- A boolean method called <em>open</em> is created to check if the given numbers are correct, and <u>returns true</u> (<u>otherwise returns false</u>).

- A boolean method method called <em>changeCombo</em> is created to check if given numbers are correct. If they are correct, it assigns new values for the combination and <u>returns true</u> (<u>otherwise returns false</u>).

5 0

2 years ago

Write a JavaScript statement to convert "Information Technology" to uppercase.

OLEGan [10]

Answer:

The JavaScript statement is

var str1 = "Information Technology";

var result = str1.toUpperCase();

Explanation:

JavaScript is used to validate the client side it means it provide the client side validation.

Following are the function of JavaScript that converted the string into uppercase.

function val()

{

var str1 = "Information Technology ";

var result = str1.toUpperCase();

}

The toUpperCase() function convert the string into uppercase in JavaScript

OUTPUT

INFORMATION TECHNOLOGY

4 0

2 years ago

Write a program that prompts the user for two numbers then outputs the result of dividing the first number by the second number

Rainbow [258]

The program is

num = int(input("Enter Numerator "))

den = int(input("Enter Denominator "))

print("quotient is ",str(num//den)," remainder is ", str(num%den))

<h3>How to create a division sign in HTML?</h3>

To create a division sign ( ÷ ) in HTML you can use any of the following codes.

÷

&div;

÷

<h3>How to divide in computer programming?</h3>

Perl code

use strict;

my $first = 15;

my $second = 5;

my $answer = $first / $second;

print "You get $answer if you divide $first by $second";

When the script above is run, it displays "You get 3 if you divide 15 by 5" on the screen.

To learn more about programming, refer

https://brainly.ph/question/4743

#SPJ4

5 0

1 year ago

If the user loads this graphic in a text only browser how will the browser describe it?

charle [14.2K]

Im going to say probably not, it wont be able to describe it but it'll search it up and show what others match the image

8 0

3 years ago

Read 2 more answers

Mix ‘em Let s1 and s2 be 2 c-strings of the same length. Write a function char* mixem(char*s1, char* s2) which returns a c-strin

Shkiper50 [21]

Answer:

See Explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace std;

char *mixem(char *s1, char *s2);

int main() {

cout << mixem("abc", "123") << endl;

cout << mixem("def", "456") << endl;

return 0;

}

char *mixem(char *s1, char *s2) {

char *result = new char[1 + strlen(s1) + strlen(s2)];

char *p1 = s1;

char *p2 = s2;

char *p = result;

while (*p1 || *p2) {

if (*p1) {

*p = *p1;

p1++;

p++;

}

if (*p2) {

*p = *p2;

p2++;

p++;

}

*p = '\0';

return result;

}

5 0

3 years ago