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3 years ago

Can someone help please? u dont have to show work so dont mind that

Mathematics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer:

Factor the numerator and denominator and cancel the common factors.

x/4+3/2 or 32/4 or Reduce the expression, if possible, by cancelling the common factors. 8 is your final answer

Step-by-step explanation:

maksim [4K]3 years ago

5 0

Answer:

Step-by-step explanation:

First, you substitute.

x + 6 / 4

26 + 6 / 4

Then, you add.

26 + 6 = 32

Finally, you divide.

32 / 4 = 8

Answer: 8

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Determine whether the triangles are similar by AA~, SSS~, SAS~, or not similar. If the triangles are similar, write a valid sing

Slav-nsk [51]

Answer:

I thinks its SAS

Step-by-step explanation:

SAS is Two sides and included agale of one triangle congruent to two sides

8 0

3 years ago

Kindly answer this question it would be really helpfull

Svetach [21]

Answer:

The values in the table, taking into account the quadratic equation, are:

x -3 -2 -1 0 1 2 3 4
y 16 9 4 1 0 1 4 9

Step-by-step explanation:

To obtain the values of the table, you must use the quadratic equation given:

y = x^2 - 2x + 1

Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:

y = x^2 - 2x + 1
y = (-3)^2 - 2*(-3) + 1
y = 9 + 6 + 1
y = 16

When x is -1

y = x^2 - 2x + 1
y = (-1)^2 - 2*(-1) + 1
y = 1 + 2 + 1
y = 4

When x is 1

y = x^2 - 2x + 1
y = (1)^2 - 2*(1) + 1
y = 1 - 2 + 1
y = 0

When x is 3:

y = x^2 - 2x + 1
y = (3)^2 - 2*(3) + 1
y = 9 - 6 + 1
y = 4

At last, the graph must be as the attached picture I give you, but remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider.

3 0

3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$