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3 years ago

Can someone help please? u dont have to show work so dont mind that

Mathematics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer:

Factor the numerator and denominator and cancel the common factors.

x/4+3/2 or 32/4 or Reduce the expression, if possible, by cancelling the common factors. 8 is your final answer

Step-by-step explanation:

maksim [4K]3 years ago

5 0

Answer:

Step-by-step explanation:

First, you substitute.

x + 6 / 4

26 + 6 / 4

Then, you add.

26 + 6 = 32

Finally, you divide.

32 / 4 = 8

Answer: 8

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Identify the period for the trigonometric function: f (t) = −2sec(t).

Agata [3.3K]

Answer:

The answer is 2pi.

Hope this helps you. Also if you practice your material better you won't need to ask. Studying is the medicine to all problems xD

3 0

3 years ago

Y + 1/2 = 7/10 solve for y

ahrayia [7]

It would be 2/10 or 1/5 simplified

7 0

3 years ago

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What is the slope of the line that passes through the points (4, 4)and (10, 7) ? Write your answer in simplest form. undefined o

jeka57 [31]

Answer:

1/2

Step-by-step explanation:

5 0

2 years ago

From a circular cylinder of diameter 10 cm and height 12 cm are conical cavity of the same base radius and of the same height is

Nataliya [291]

<h3>Volume of the remaining solid = 628 cm^2</h3>

<h3>Whole surface area = 659.4 cm^2</h3>

Step-by-step explanation:

Now, Given that:-

Diameter (d) = 10 cm

So, Radius (r) = 10/2 = 5cm

Height of the cylinder = 12cm.

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= > \pi \times {5}^{2} \times 12 {cm}^{3} = 300\pi {cm}^{3}$

Radius of the cone = 5 cm.

Height of the cone = 12 cm.

$slant \: height \: of \: the \: cone \: = \sqrt{ {h}^{2} + \: {r}^{2} }$

$= > \sqrt{ {5}^{2}+{12}^{2} } cm \: = 13cm$

Volume of the cone = 1/3 *πr^2h

$= > \frac{1}{3} \pi \times {5}^{2} \times 12 {cm}^{3} = 100\pi {cm}^{3}$

therefore, the volume of the remaining solid

$= 300\pi {cm}^{3} - 100\pi {cm}^{3} \\ = 200 \times 3.14 {cm}^{3} = 628 {cm}^{3}$

Curved surface of the cylinder =

$2\pi \: rh \: = 2\pi \times 5 \times 12 {cm}^{2} \\ = 120\pi {cm}^{2} .$

$curved \: surface \: of \: the \: cone \: = \pi \: rl \\ = \pi \times 5 \times 13 {cm}^{2} \\ = 65\pi {cm }^{2} \\ area \: of \: (upper)circular \: base \: \\ of \: cylinder \: = \\ = \pi \: {r}^{2} = \pi \times {5}^{2}$

therefore, The whole surface area of the remaining solid

= curved surface area of cylinder + curved surface area of cone + area of (upper) circular base of cylinder

$= 120\pi {cm}^{2} + 65\pi {cm }^{2} + 25 \pi {cm}^{2} \\ = 210 \times 3.14 {cm}^{2} = 659.4 {cm}^{2}$

<h3>Hope it helps you!!</h3>

6 0

2 years ago

Which of the following points lies in the solution set to the system of inequalities shown below

Oduvanchick [21]

Answer:

1,2, and 4

Step-by-step explanation:

I attached a picture with the graph

y= -4 is a straight horizontal line (red line) and

y≤10 will give a horizontal line passing trough y=10 (blue line)

the solution is all points under and on the line y=10

1, 2, and 4 are part of the solution set

(the blue area is the solution of the system of equations)

7 0

3 years ago

Read 2 more answers