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natita [175]
3 years ago
15

Can someone help me please

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
64 FL oz

1 pint is 12 fl oz.

Since you're looking for 4 pints, you multiply everything by 4.


1 x 4 = 4
12 x 4 = 64
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Help Please I'm Out Of Time ;(
trasher [3.6K]

Answer:

Total area = 31.5 unit²

Step-by-step explanation:

Assume 1 block = 1 unit²

Divide diagram into 3 part

1. 5 by 5 block square

2. 2 by 2 block triangle(1)

2. 3 by 3 block triangle(2)

Area of square = side × side

Area of square = 5 × 5

Area of square = 25 unit²

Area of triangle(1) = [1/2][base][height]

Area of triangle(1) = [1/2][2][2]

Area of triangle(1) = 2 unit²

Area of triangle(2) = [1/2][base][height]

Area of triangle(2) = [1/2][3][3]

Area of triangle(2) = 4.5 unit²

Total area = Area of square + Area of triangle(1) +Area of triangle(2)

Total area = 25 unit² + 2 unit² + 4.5 unit²

Total area = 31.5 unit²

6 0
3 years ago
I have been stuck on the problem for so long. please help me:
Xelga [282]

Answer:

D-2

Step-by-step explanation:

You can use elimination to get the value of y. Move numbers to one side and x and ys to the other side. To use elimination, multiply the first equation with 2. You will get 2x+2y=24. add it with the equation below. y will be eliminated and you will get the value of x. X=10. Plug in x and get the y value. Y=2

6 0
2 years ago
The volume of a room is 640 cubic feet. If the length is 10 feet and the width is 4 feet, find the heigh
Allisa [31]

Answer:

16

Step-by-step explanation:

10 · 4 = 40

640/40= 16

4 0
2 years ago
What is 6476 divided by 12
pentagon [3]
6467/12 is 539.667 ;))
4 0
3 years ago
Read 2 more answers
What are the solutions to the following system?
bija089 [108]

The solutions are (\sqrt{2},-1) \text { and }(-\sqrt{2},-1).

Solution:

Given equation:

-2 x^{2}+y=-5

Add 2 x^{2} on both sides.

-2 x^{2}+y+2 x^{2}=-5+2 x^{2}

y=-5+2 x^{2} -------- (1)

y=-3 x^{2}+5 (given)  -------- (2)

Equate (1) and (2).

-5+2 x^{2}=-3 x^{2}+5

Add 3 x^{2} on both sides.

-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}

-5+5x^{2}=5

Add 5 on both sides.

-5+5x^{2}+5=5+5

5x^{2}=10

Divide by 5 on both sides, we get

x^{2}=2

Taking square root on both sides, we get

x=\sqrt{2}, x=-\sqrt{2}

Substitute x=\sqrt{2} in (1).

y=-5+2(\sqrt{2})^2

y=-5+4

y=-1

Substitute x=-\sqrt{2} in (1).

y=-5+2(-\sqrt{2})^2

y=-5+4

y=-1

Therefore the solutions are (\sqrt{2},-1) \text { and }(-\sqrt{2},-1).

Option C is the correct answer.

6 0
3 years ago
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