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Karo-lina-s [1.5K]
3 years ago
11

7. The time taken to assemble a car in a certain plant is a random variable having a normal distribution of 20 hours and a stand

ard deviation of 2 hours. What is the probability that a car can be assembled at this plant in a period of time a) less than 19.5 hours
Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer: The probability is 0.4

Step-by-step explanation:

Since the time taken to assemble a car in a certain plant is a random variable having a normal distribution, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = time taken to assemble cars

µ = mean time

σ = standard deviation

From the information given,

µ = 20 hours

σ = 2 hours

We want to find the probability that a car can be assembled at this plant in a period of time less than 19.5 hours. It is expressed as

P(x < 19.5) = 1 - P(x ≤ 19.5)

For x = 19.5

z = (19.5 - 20)/2 = - 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.4

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Consider the paraboloid z=x2+y2. The plane 8x−5y+z−2=0 cuts the paraboloid, its intersection being a curve. Find "the natural" p
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Answer:

The parametrization of the curve on the surface is

c(t) =  [x(t) , y(t), z(t)] \equiv [\frac{\sqrt{97} }{2} cost - 4 , \frac{\sqrt{97} }{2}  sint  + \frac{5}{2} ,  5\frac{\sqrt{97} }{2}  sint   -8 \frac{\sqrt{97} }{2} cost +\frac{93}{2} ]

Where

   x =  \frac{\sqrt{97} }{2} cost - 4

    y = \frac{\sqrt{97} }{2}  sint  + \frac{5}{2}

z = 5\frac{\sqrt{97} }{2}  sint   -8 \frac{\sqrt{97} }{2} cost +\frac{93}{2}

Step-by-step explanation:

From the question we are told that

The equation for the paraboloid is z = x^2 + y^2

The equation of the plane is 8x  - 5y + z -2  = 0

Form the equation of the plane we have that

z = 5y -8x +2

So

x^2 + y^2 = 5y -8x +2

=> x^2 + 8x + y^2 -5y = 2

Using completing the square method to evaluate the quadratic equation we have

(x + 4)^2 + (y - \frac{5}{2} )^2  = 2 +(\frac{5}{2} )^2 + 4^2

(x + 4)^2 + (y - \frac{5}{2} )^2  = \frac{97}{4}

(x + 4)^2 + (y - \frac{5}{2} )^2 = ( \frac{\sqrt{97} }{2} )^2

representing the above equation in parametric form

(x + 4) = \frac{\sqrt{97} }{2} cost , (y -\frac{5}{2} ) = \frac{\sqrt{97} }{2} sin t

x =  \frac{\sqrt{97} }{2} cost - 4

y = \frac{\sqrt{97} }{2}  sint  + \frac{5}{2}

So from z = 5y -8x +2

z = 5[\frac{\sqrt{97} }{2}  sint  + \frac{5}{2}] -8[  \frac{\sqrt{97} }{2} cost - 4] +2

z = 5\frac{\sqrt{97} }{2}  sint  + \frac{25}{2} -8 \frac{\sqrt{97} }{2} cost + 32 +2

z = 5\frac{\sqrt{97} }{2}  sint   -8 \frac{\sqrt{97} }{2} cost +\frac{93}{2}

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