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Fantom [35]
3 years ago
10

What is the fraction is less than 5/6 and has denominator of 8?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
7 0

Denominator is the number which appears at the bottom of fraction so the fraction we want is in the form X/8 and also less than 5/6

Lets start from changing the values of X from 1.

1/8 = 0.125 and 5/6 = 0.8333

2/8 = 0.25

3/8 = 0.375

4/8 = 0.5

5/8 = 0.625

6/8 = 0.75

7/8 = 0.875, this is greater than 5/6

<span>So, the fractions with denominator 8 and less than 5/6 are 1/8, 2/8, 3/8, 4/8, 5/8 and 6/8</span>

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podryga [215]

Answer:

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Step-by-step explanation:

4 0
3 years ago
in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
The number 3453 has two 3 why does each 3 have different value
Usimov [2.4K]
The two 3s have different place values. The 3 on the left is in thousands place while the 3 on the right is in the ones place. we can also look at this vc by separating each digit ( 3000 + 400 + 50 + 3)

while the digits are the same, their place determines the value
3 0
3 years ago
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Solve for x on the interval 0≤x&lt;2pi<br><br> cos(3x)=1/2
Ede4ka [16]

We will see that the solution in the given interval is: x = 0.349 radians.

<h3>How to solve equations with the variable in the argument of a cosine?</h3>

We want to solve:

cos(3*x) = 1/2

Here we must use the inverse cosine function, Acos(x). Remember that:

cos(Acos(x)) = Acos(cos(x)) = x.

If we apply that in both sides, we get:

Acos( cos(3x) ) = Acos(1/2)

3*x = Acos(1/2)

x = Acos(1/2)/3 = 0.349

So x is equal to 0.349 radians, which belongs to the given interval.

If you want to learn more about trigonometry, you can read:

brainly.com/question/8120556

7 0
2 years ago
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Step-by-step explanation:

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