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Reika [66]
3 years ago
13

The ph of a solution for which [OH]= 1.0 x 10^-4 is? A 10 B 14 C 11 D 9 E 7

Chemistry
1 answer:
zhenek [66]3 years ago
8 0
To find pH, use the following formula ---> pH= - log [H+]

so first we need to calculate the [H+] concentration using the OH concentration. to do this, we need to use this formula--> 1.0x10-14= [H+] X [OH-], so we solve for H+ and plug in

[H+]= 1.0X10-14/[OH-]---> 1.0 x 10-14/ 1.0 x 10-4= 1.0 x 10-10

now that we have the H+ concentration, we can solve of pH

pH= -log (1.0x10-10)= 10

answer is A
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<u>Answer:</u> The de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

<u>Explanation:</u>

Kinetic energy is the measure of temperature of the system.

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Putting values in above equation, we get:

E=\frac{3}{2}\times 1.38\times 10^{-23}J/K\times 30K\\\\E=6.21\times 10^{-22}J

  • Calculating the mass of 1 molecule of hydrogen gas:

Conversion factor used:  1 kg = 1000 g

1 mole of hydrogen gas has a mass of 2 grams or 2\times 10^{-3}kg  

According to mole concept:

6.022\times 10^{23} number of molecules occupy 1 mole of a gas.

As, 6.022\times 10^{23} number of hydrogen molecules has a mass of 2\times 10^{-3}kg

So, 1 molecule of hydrogen will have a mass of = \frac{2\times 10^{-3}kg}{6.022\times 10^{23}}\times 1=3.32\times 10^{-27}kg

  • To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

\lambda=\frac{h}{\sqrt{2mE_k}}

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\lambda = De-Broglie's wavelength = ?

h = Planck's constant = 6.624\times 10^{-34}Js

m = mass of 1 hydrogen molecule = 3.32\times 10^{-27}kg

E_k = kinetic energy of the particle = 6.21\times 10^{-22}J

Putting values in above equation, we get:

\lambda=\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 3.32\times 10^{-27}kg\times 6.21\times 10^{-22}J}}

\lambda=3.26\times 10^{-10}m=3.26\AA    (Conversion factor: 1\AA=10^{-10}m )

Hence, the de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

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