Answer:
When sodium hydroxide (NaOH) dissolves in water, it separates into positively - charged sodium ions (cations) and negatively - charged hydroxide ions (anions).
Hope this helped.
Answer:
The collision theory is defined as the rate of a reaction is proportional to the rate of reactant collisions.
Explanation:
The reacting species should collide with orientation that allows contract between the atoms that will become bonds together in the product.
The collision occurs with adequate energy to permit mutual penetration of the reacting species. The two physical factors based on the orientation and energy of collision, the following reaction with carbon monoxide with oxygen is considered.
2CO(g) + O2(g) → 2CO2 (g)
After collision between the carbon monoxide and oxygen the reaction is
CO(g) + O2(g) → CO2 (g) + O(g)
Based on the theories of chemical reaction the molecules collide with sufficient amount of energy an activated complex is formed.
Hey there!:
density = mass / volume
1.84 g/mL = 12 g / V
V = 12 / 1.84
V = 6.521 mL
hope this helps!
Answer: The element Na (Sodium) is getting oxidized and Hydrogen is getting reduced.
Explanation:
Oxidation reactions are the reactions in which addition of oxygen takes place.
Reduction reactions are the reactions in which loss of oxygen takes place.
For a given reaction:
Sodium is getting oxidized because there is an addition of reaction with that element.
Hydrogen is getting reduced because there is a removal of oxygen with that element.
<span>Answer:
Nothing is balanced in your final equation: not H, not O, not Cr, not I and your charges aren't either.
Start with your 2 half reactions:
I- --> IO3-
Cr2O72- --> 2 Cr3+
Balance O by adding H2O:
I- + 3 H2O --> IO3-
Cr2O72- --> 2 Cr3+ + 7H2O
Balance H by adding H+:
I- + 3 H2O --> IO3- + 6 H+
Cr2O72- + 14 H+ --> 2 Cr3+ + 7H2O
Balance charge by adding e-:
I- + 3 H2O --> IO3- + 6 H+ + 6 e-
Cr2O72- + 14 H+ + 6 e- --> 2 Cr3+ + 7H2O
Since the numbers of electrons in your two half reactions are the same, just add them and simplify to give:
Cr2O72- + I- + 8 H+ --> IO3- + 2 Cr3+ + 4 H2O</span>
