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abruzzese [7]
3 years ago
7

What were schools like the first half of Henry's life? How do you think this affect his education? Answer BOTH questions in comp

lete sentences.
Chemistry
1 answer:
Lorico [155]3 years ago
3 0

Answer:

Not sure.

Explanation:

Who is Henry?

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Today, nuclear power plants rely on fission. While fusion reactions have been used in nuclear bombs, many scientists and enginee
Zigmanuir [339]

Explanation:

nuclear fusion yields more energy than nuclear fission and the products of the reaction are not radioactive

5 0
3 years ago
Why does it take so much heat and pressure to create helium and other elements?
ehidna [41]

Answer:

To break down the nucleus of an atom

Explanation:

Remember to change from one element to another, is necessary to add protons, neutrons and electrons,in most of the cases.

The take an electron from an atom you need certain energy, but they are in the outside part of the atom so is not as much energy as the one is necessary to take one neutron or proton from the inside part of an atom.

In this way, is a must to have a combination of pressure and heat to destabilize an atom and take some of this subatomic particles.

4 0
3 years ago
Phase change is based on the_________, which states that phase change occurs with changing average kinetic energy. a. Law of con
AleksAgata [21]

Answer:

d but I'm not sure.............

8 0
3 years ago
What is the volume of 60 g of ether if the density of ether is 70 g/mL
NNADVOKAT [17]
V = 60.0 g/ 0.70 g/mL = 85.7 mL Hope this helps! ;D
4 0
4 years ago
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
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