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Lady bird [3.3K]
3 years ago
11

A runner wants to run 13.1 km . She knows that her running pace is 6.2 mi/h .How many minutes must she run? Hint: Use 6.2 mi/h a

s a conversion factor between distance and time.
Chemistry
1 answer:
frutty [35]3 years ago
4 0

Answer:

  • <u>79 minutes</u>

Explanation:

1)<u> Convert the distance, 13.1 km to miles</u>

  • Conversion factor:

        1 = 1 mi / 1.61 km

  • 13.1 km [ 1 mi /  1.61 km ] = 8.1336 mi

2)<u> Use 6.2 mi/h as a converstion factor between distance and time</u>

  • 8.1366 mi × 1 / [6.2 mi/h] = 1.3124 h

3) <u>Convert 1.3124 h to minutes</u>

  • 1.3124 h × [ 60 min/h] = 78.7 min

Rounding to the nearest minutes (two significant figures):

  • 79 min ← answer
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A. Step 1:

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C12H26(l) + O2(g) —> CO2(g) + H2O(g)

A. Step 2:

Balancing the equation.

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There are 26 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 13 in front of H2O as illustrated below:

C12H26(l) + O2(g) —> 12CO2(g) + 13H2O(g)

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We'll by obtaining the number of mole of C12H26 in 0.450 kg of C12H26. This is illustrated below:

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Mass of C12H26 = 0.450 kg = 0.450x1000 = 450g

Number of mole of C12H26 =?

Number of mole = Mass/Molar Mass

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Determination of the volume of CO2 produced by the reaction.

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The volume of CO2 produced by the reaction can b obtained by applying the ideal gas equation as follow:

PV = nRT

1 x V = 31.8 x 0.082 x 292

V = 761.42 L

Therefore, the volume of CO2 produced is 761.42 L

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