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Lady bird [3.3K]
3 years ago
11

A runner wants to run 13.1 km . She knows that her running pace is 6.2 mi/h .How many minutes must she run? Hint: Use 6.2 mi/h a

s a conversion factor between distance and time.
Chemistry
1 answer:
frutty [35]3 years ago
4 0

Answer:

  • <u>79 minutes</u>

Explanation:

1)<u> Convert the distance, 13.1 km to miles</u>

  • Conversion factor:

        1 = 1 mi / 1.61 km

  • 13.1 km [ 1 mi /  1.61 km ] = 8.1336 mi

2)<u> Use 6.2 mi/h as a converstion factor between distance and time</u>

  • 8.1366 mi × 1 / [6.2 mi/h] = 1.3124 h

3) <u>Convert 1.3124 h to minutes</u>

  • 1.3124 h × [ 60 min/h] = 78.7 min

Rounding to the nearest minutes (two significant figures):

  • 79 min ← answer
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148.04 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

NO(g) + 1/2 O₂(g) → NO₂(g)      ΔH°rxn = -114.14 kJ/mol

We can find the standard enthalpy of formation (ΔH°f) of NO(g) using the following expression.

ΔH°rxn = 1 mol × ΔH°f(NO₂(g)) - 1 mol × ΔH°f(NO(g)) - 1/2 mol × ΔH°f(O₂(g))

ΔH°f(NO(g)) = 1 mol × ΔH°f(NO₂(g)) - ΔH°rxn - 1/2 mol × ΔH°f(O₂(g)) / 1 mol

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The elements are samarium (Sm) and silver (Ag).  

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<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

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<em>  </em>   Y       5<em> </em>2  2 +½  

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    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

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