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Elden [556K]
3 years ago
5

Which is equivalent to 4/9 1/2^x

Mathematics
2 answers:
marta [7]3 years ago
4 0
You have not provided a list of possible equivalents to (4/9)(1/2)^x.  But you can still try to simplify (4/9)(1/2)^x.

Start with (1/2)^x.  This is the same as         1^x
                                                                     -------
                                                                       2^x

Now multiply both sides by (4/9):

                         4(1)
(4/9)(1/2)^x =  ---------
                          2^x

or         4
         --------
           2^x

You could also write this as 

   2 (2)            2^1
----------  = 2 --------  = 2*2^(1-x)    or 2[2^(1-x)]
   2^x             2^x
nevsk [136]3 years ago
3 0

Answer: It's B

9^1/8x


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1
kakasveta [241]
1/8 or D, because 1/2 divied by 4 equals 1/8. Hope I helped! I need some help on one question for me.

7 0
3 years ago
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Very Confused please help!
Nataly_w [17]
We know that<span>
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. 
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that</span>
<span> Circle 1 is centered at (5,8) and has a radius of 8 centimeters
 Circle 2 is centered at (1,-2) and has a radius of 4 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
the transformation has the following rule</span>
(x,y)--------> (x-4,y-10)
so
(5,8)------> (5-4,8-10)-----> (1,-2)
so
center circle 1 is now equal to center circle 2 
<span>The circles are now concentric (they have the same center)
</span>
step 2
<span>A dilation is needed to decrease the size of circle 1 to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 4/8----> 0.5

radius circle 1 will be=8*scale factor-----> 8*0.5-----> 4 cm
radius circle 1 is now equal to radius circle 2 

<span>A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

the answer is
</span>
</span>The circles are similar because you can translate Circle 1 using the transformation rule (x-4,y-10) and then dilate it using a scale factor of (0.5)
4 0
3 years ago
Select all the expressions with accurately written descriptions.
Paha777 [63]
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand. 

1. True
2 times y and 6                                                          -------->(2y+6)
the square of the sum of "2 times y and 6"             -------->(2y+6)^2
8 times  "the square of the sum of 2 times y and 6"------> 8(2y+6)^2

2. True
the difference of x and 7                            -------->(x-7)
9 and x                                                         -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x)  (x-7)

3. True
difference of 5 times x and 3   -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2

4. False
The description should be: the product of 7 and the square of x
the product of 7 and x                        -------->(7x)
the square of the product of 7 and x -------->(7x)^2

5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4

6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8                -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and....                ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
5 0
3 years ago
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4/5(p+1)=1 wgat equals p​
jeka94

Answer:

p= 1/4 or 0.25

Step-by-step explanation:

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Solve for y ; -2y - 2x =4
Deffense [45]
I think this is what you want to do

Your welcome

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