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Nutka1998 [239]

3 years ago

11

Solve each system of linear Equations x+y=5 x-3y=3

1 answer:

JulijaS [17]3 years ago

7 0

X+y=5 y=5-x

x-3y=3
x-3(5-x)=3
x-15+3x=3
4x=18
x=4.5

y=5-x
y=0.5

check
x+y=5 4.5+0.5=5
x-3y=3 4.5-1.5=3

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10th grade geometry <br> Select statements that are true about angles on diagram

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Answer:

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Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same

Hoochie [10]

we have

$y=\frac{2}{5}x-5$

Let's Isolate the variable y in each of the cases and then compare with Fiona's equation to determine the solution of the problem

case A) $x-\frac{5}{4}y= \frac{25}{4}$

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Divide by $5$ both sides

$y=\frac{4}{5}x-5$

therefore

the case A) is not equal to Fiona's equation

case B) $x-\frac{5}{2}y= \frac{25}{4}$

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therefore

the case B) is not equal to Fiona's equation

case C) $x-\frac{5}{4}y= \frac{25}{2}$

Multiply by $4$ both sides

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Divide by $5$ both sides

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the case C) is not equal to Fiona's equation

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Divide by $5$ both sides

$y=\frac{2}{5}x-5$

therefore

the case D) is equal to Fiona's equation

<u>the answer is</u>

$x-\frac{5}{2}y= \frac{25}{2}$

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jasenka [17]

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A rectangle has a width of 2.5. When the length of this rectangle is decreased by 5 inches, the new area of the rectangle is 17.

kati45 [8]

<h3><u>Part A: An equation to represent this situation, where x represents the original length of the rectangle is:</u></h3>

$17.5 = (x-5) \times 2.5$

<h3><u>Part B: Original length of the rectangle is 12 inches</u></h3>

<em><u>Solution:</u></em>

Given that,

A rectangle has a width of 2.5

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<em><u>The area of rectangle is given as:</u></em>

$Area = length \times width$

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