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fiasKO [112]
3 years ago
14

Find all numbers such that a third of a number increased by half that number is at least 3 less than that same number.

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0
N/3 + n/2 >= n - 3

2n/6 + 3n/6 >= n - 3

5n/6 >= n - 3

5n >= 6n - 18

-n >= -18

n <= 18
kaheart [24]3 years ago
6 0

Answer:

All the numbers are less than and equal to 18.

Step-by-step explanation:

To find : All numbers such that a third of a number increased by half that number is at least 3 less than that same number ?

Solution :

Let the number be 'x',

A third of a number is \frac{x}{3}

Half that number is \frac{x}{2}

3 less than that same number is x-3

A third of a number increased by half that number is at least 3 less than that same number is written as,

\frac{x}{3}+\frac{x}{2}\geq x-3

\frac{2x+3x}{6}\geq x-3

\frac{5x}{6}\geq x-3

5x\geq 6x-18

5x-6x\geq -18

-x\geq -18

x\leq 18

Therefore, all the numbers are less than and equal to 18.

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