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fiasKO [112]
3 years ago
14

Find all numbers such that a third of a number increased by half that number is at least 3 less than that same number.

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0
N/3 + n/2 >= n - 3

2n/6 + 3n/6 >= n - 3

5n/6 >= n - 3

5n >= 6n - 18

-n >= -18

n <= 18
kaheart [24]3 years ago
6 0

Answer:

All the numbers are less than and equal to 18.

Step-by-step explanation:

To find : All numbers such that a third of a number increased by half that number is at least 3 less than that same number ?

Solution :

Let the number be 'x',

A third of a number is \frac{x}{3}

Half that number is \frac{x}{2}

3 less than that same number is x-3

A third of a number increased by half that number is at least 3 less than that same number is written as,

\frac{x}{3}+\frac{x}{2}\geq x-3

\frac{2x+3x}{6}\geq x-3

\frac{5x}{6}\geq x-3

5x\geq 6x-18

5x-6x\geq -18

-x\geq -18

x\leq 18

Therefore, all the numbers are less than and equal to 18.

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Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo
elena55 [62]

Answer:

\displaystyle y-5=-\frac{10}{9}(x+6)

Or:

\displaystyle y+5=-\frac{10}{9}(x-3)

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

y-y_1=m(x-x_1)

Thus, first, we need to find the slope. We can use the slope formula:

\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

\displaystyle y-(5)=-\frac{10}{9}(x-(-6))

Or, fully simplified:

\displaystyle y-5=\frac{-10}{9}(x+6)

Using the other point, we will acquire:

\displaystyle y-(-5)=-\frac{10}{9}(x-(3))

Or, simplified:

\displaystyle y+5=-\frac{10}{9}(x-3)

8 0
2 years ago
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