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oksano4ka [1.4K]
3 years ago
8

Which contribution is a modification to Dalton's original atomic model? a.Atoms are indivisible. b. Electrons are scattered in a

n atom.c. Atoms are the smallest unit of an element. d.Atoms of the same element have the same properties.
Chemistry
2 answers:
Rzqust [24]3 years ago
7 0

Answer: b. Electrons are scattered in an atom

Explanation:

Postulates of Dalton's atomic theory:

a) Atom are indivisible and are the smallest unit of any matter.

b) Atoms of same element have same mass.

c) Atoms of different elements differ in mass.

d) Elements combines with each other in whole number to form compounds.

Electrons are scattered in an atom which was given by J.J Thomson in his plum pudding model.

Thus the modification to Dalton's original atomic model is Electrons are scattered in an atom

Anastasy [175]3 years ago
6 0
<span>B. Electrons are scattered in an atom. Dalton only came to the conclusion at atoms existed, not their contents. He did this by using gases and making them react and made observations about the gases.</span>
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15.772%

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As an example of the processes depicted in this figure, consider a sample of water. When gaseous water is cooled sufficiently, the attractions between H2O molecules will be capable of holding them together when they come into contact with each other; the gas condenses, forming liquid H2O. For example, liquid water forms on the outside of a cold glass as the water vapor in the air is cooled by the cold glass.

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Hopefully that helps!

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The cl-cl bond will react more readily, because it has a
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3 years ago
In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3
Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------>  Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3  = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles ×  2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced  is obtained from;

2 moles of HNO3  yields 1 mole of Ba(NO3)2

0.41 moles of HNO3  yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of  Ba(NO3)2  = 0.21 moles  × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

8 0
3 years ago
What is the amount, in moles, of each elemental sample? a. 11.8 g Ar b. 3.55 g Zn c. 26.1 g Ta d. 0.211 g Li
spayn [35]

Answer:

A. 0.295 mole

B. 0.055 mole

C.0.144 mole

D. 0.03 mole

Explanation:

To find the amount in moles, we simply use a mathematical relation that connects mass, atomic mass and number of moles.

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D. Atomic mass of lithium is 7

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8 0
3 years ago
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