Energy used by the cell
1 answer:
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Explanation:
The given data is as follows.
Volume of water = 0.25
Density of water = 1000
Therefore, mass of water = Density × Volume
=
= 250 kg
Initial Temperature of water () =
Final temperature of water =
Heat of vaporization of water () at
is 2133 kJ/kg
Specific heat capacity of water = 4.184 kJ/kg/K
As 25% of water got evaporated at its boiling point () in 60 min.
Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg
Heat required to evaporate = Amount of water evapotaed × Heat of vaporization
= 62.5 (kg) × 2133 (kJ/kg)
= kJ
All this heat was supplied in 60 min = 60(min) × 60(sec/min) = 3600 sec
Therefore, heat supplied per unit time = Heat required/time = = 37 kJ/s or kW
The power rating of electric heating element is 37 kW.
Hence, heat required to raise the temperature from to
of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)
= 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)
= 125520 kJ
Time required = Heat required / Power rating
=
= 3392 sec
Time required to raise the temperature from to
of 0.25
water is calculated as follows.
= 56 min
Thus, we can conclude that the time required to raise the temperature is 56 min.
Answer: 40731.8 grams of this gasoline would fill a 14.6gal tank
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of gasoline = ?
Density of the gasoline =
Volume of the gasoline = 14.6gal = 55267.01 ml (1gal=3785.41ml)
Putting in the values we get:
Thus 40731.8 grams of this gasoline would fill a 14.6gal tank
Given :
If I inhale 2.2 liters of gas at a temperature of 180 C and it heats to a temperature of 380 C in my lungs.
To Find :
The new volume of the gas.
Solution :
Since, their is no information about pressure, so we will assume that pressure is constant.
We know, relation between temperature and volume in constant pressure is :
Putting all given values in above equation, we get :
Hence, this is the required solution.