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3 years ago

The cl-cl bond will react more readily, because it has a

Chemistry

1 answer:

bekas [8.4K]3 years ago

5 0

Answer: bond energy

Explanation:

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222 g of MTBE (CO(CH3)4) are added to gasoline, resulting in a total volume of 2 L of reformulated gas (RFG). Assume that the de

Eva8 [605]

Answer:

Explanation:

From the information given:

(a)

$Concentration \ in \ mg/L = \dfrac{Mass \ of \ MTBE \ in \ mg}{Total \ volume (in \ L)}$

$Concentration \ in \ mg/L = \dfrac{222 \times 10^3 \ mg}{22}$

$Concentration \ in \ mg/L = 111 \times 10^3 \ mg/L$

(b)

$number \ of \ mole s= \dfrac{mass}{molar \ mass } \\ \\ number \ of \ mole s=\dfrac{222 \ g}{88.15 \ g/mol} \\ \\ \mathbf{= 2.518 mol}$

(c)

$w/w \ percentage = \dfrac{mass \ of \ MTBE }{mass \ of \ solution (RFG)}\times 100\%$

$where; \\ \\ mass \ of \ (RFG) = 2L \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 2000 ml \times 0.70 g/mL \\ \\ mass \ of \ (RFG) = 1400 g$

∴

$w/w \ percentage = \dfrac{222 \ g}{1400 \ g}\times 100\% = \mathbf{15.8\%}$

(d)

$Volume of MTBE =\dfrac{mass \ of \ MTBE}{density \ of \ MTBE}$

$Volume \ of \ MTBE = 300 \ mL\\$

∴

$v/v\% = \dfrac{volume \ of \ MTBE}{volume \ of \ RFG} \\ \\ v/v\% =\dfrac{300 \ mL}{2000 \ mL}\times 100\% \\ \\ \mathbf{v/v\% = 15.00\%}$

(e)

$From \the \ given \ information; \\ \\ 2.5184 \ moles\ of \ MTBE contain \ 2.5184 \ mole of oxygen$

∴

$mass of oxygen MTBE = 2.5284 mol \times 16\ g/mol \\ \\ mass of oxygen MTBE = 40.3 9 \ g\\ \\ mass\ of \ RFG = 1400 g$

∴

$\% w/w = \dfrac{mass \ of \ oxygen}{mass \ of RFG }=\dfrac{40.22 \ g}{1400 \ g} \times 100\%$

$\% w/w == 2.88\%$

3 0

3 years ago

Read 2 more answers

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. a. 2,4-dinitro

ludmilkaskok [199]

Compounds in order of increasing acidity will be written as d<c<b<a.

<h3>What is acidity?</h3>

The quantity of hydroxyl ions that a basic molecule may create in an aqueous solution is what is known as the acidity of bases. The quantity of hydronium ions that a substance may create in an aqueous solution determines how basic an acid is.

a, b are more acidic than c and d because of OH group attached to sp2 hybridised carbon which provide resonance stability for conjugate base

in c f has -I effect which increases acidity in a, NO2 has -m effect which increases acidity so increasing order is d<c<b<a

that is cyclohexanol < 2,4-difluorocyclohexanol < phenol < 2,4-dinitrophenol

to learn more about acidity go to -

brainly.com/question/19584961

#SPJ4

3 0

2 years ago

Which statement about forces is true?

Elodia [21]

Answer:

Explanation:

because forces act on an object and make it change direction based upon strength hope this helps.

4 0

3 years ago

The fictional element, marvellium has 4 isotopes with mass numbers of 21, 22,24, and 28 amu. Each isotope is found in equal amou

natita [175]

Answer:

The answer to that question is 24 AMU.

Explanation:

I know this because i got the answer correct on the quiz. To get the average, you just add the 4 atomic masses given to you together then divide by 4.

3 0

3 years ago

Write the Ksp expression for the sparingly soluble compound chromium(III) hydroxide, Cr(OH)3.

Klio2033 [76]

Answer and Explanation: Ksp is the Solubility Product Constant and is the equilibrium constant that happens when a solid is dissolved in an aqueous solution.

The dissolution of chromium (III) hydroxide:

$Cr(OH)_{3}_{(s)}$ ⇄ $Cr^{3+}_{(aq)} + 3OH^{-}_{(aq0)}$

Every equilibrium constant is of the form:

$K = \frac{[products]^{coefficient}}{[reagents]^{coefficient}}$

Then,

$K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}$

The reagent is not included because solids don't take part in euqilibrium constants.

<u>So, Ksp of chromium (III) hydroxide is </u> $K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}$ <u />

4 0

3 years ago