The minerals hematite (Fe₂O₃) and magnetite (Fe₃O₄) exist in equilibrium with atmospheric oxygen:4Fe₃O₄(s) + O₂(g) ⇄ 6Fe₂O₃(s) K

Question

2 years ago

15

p = 2.5×10⁸⁷ at 298K (c) Calculate Kc at 298 K.

1 answer:

iren2701 [21] · Answer 1 · 2023-06-02T10:43:33+03:00

Kc at 298K is Kc = 1 × 10^84.

Calculation:

The relation between Kp and Kc is

Kp = KcRT

The value of Kp is known

We can calculate the value of Kc with this

R = 8.3145 J mol^−1 K^−1 .

T = 298K

Kp = KcRT

2.5×10⁸⁷ = Kc × 8.3145 × 298

2.5×10⁸⁷ = Kc × 2477.572

Kc = 1 × 10^84

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