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vampirchik [111]
3 years ago
7

Helppp 8th grade algebra

Mathematics
1 answer:
Elanso [62]3 years ago
6 0
The triangles are equilateral.

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Can someone help me with translation
Arte-miy333 [17]

Answer:

  P' = (4, 4)

Step-by-step explanation:

T(x, y) is a function of x and y. Put the x- and y-values of point P into the translation formula and do the arithmetic.

  P' = T(8, -3) = (8 -4, -3 +7) = (4, 4)

_____

<em>Comment on notation</em>

The notation can be a little confusing, as the same form is used to mean different things. Here, P(8, -3) means <em>point P</em> has coordinates x=8, y=-3. The same form is used to define the translation function:

  T(x, y) = (x -4, y+7)

In this case, T(x, y) is not point T, but is <em>a function named T</em> (for "translation function") that takes arguments x and y and gives a coordinate pair as a result.

3 0
3 years ago
A skateboard ramp make a 27 angle with the ground to the nearest foot how high is the ramp
Zinaida [17]
You have to use sin/cos/tan values

5 0
3 years ago
Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
inna [77]
(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2
\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
6 0
3 years ago
Pls help I’ve already tried 3/11 but it says it wrong
love history [14]

Answer:

12

Step-by-step explanation:

Alr so correct me if I'm wrong but I think you made a mistake. It says find 44 of those rectangles. You found just 1 in that case which the area is 3/11. You have to do 3/11 X 44 which is

3/11 x 44/1 = 132/11 = 12.

As I said, correct me if I'm wrong.

Hope this Helps!

5 0
2 years ago
Find the area of the parallelogram: b= 10 ft, h= 8 ft
Kazeer [188]

Answer:

i dont think you have the full question here...

4 0
3 years ago
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