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GalinKa [24]
4 years ago
9

3/5 as a percent. Please help

Mathematics
2 answers:
Kay [80]4 years ago
7 0
It has to be 60% because of the way you divide this problem
Tanzania [10]4 years ago
5 0
Is 0.60 if you move left its 60% so 60%
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Write a number of your choice, using the following clues:
guapka [62]

Answer:

90

Step-by-step explanation:

90÷2= 45

90÷3=30

8 0
3 years ago
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What is the LCM of 6 and 18? A. 12 B. 36 C. 18 D. 6
Arisa [49]
The lcm of 6 and 18 is C.)18
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3 years ago
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A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

  • 12 ft parallel to the river
  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
a rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension
Ne4ueva [31]
Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"

So, the length the rectangle is 2" and the width is 3"
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4 years ago
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hammer [34]

Answer:

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