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padilas [110]
3 years ago
12

Assume the rate of inflation is 5​% per year for the next 2 years. What will be the cost of goods 2 years from​ now, adjusted fo

r​ inflation, if the goods cost ​$280.00 ​today?
@Jimthompson5910
Mathematics
1 answer:
kirza4 [7]3 years ago
7 0
The equation for inflation is
A = P*(1+r)^t
which is an exponential growth equation (if r > 0). If r < 0, then we have deflation.

where...
A = final price after t years
P = initial starting price
r = rate of inflation in decimal form 
t = number of years

In this case, 
A = unknown (we're solving for this)
P = 280 is the starting price
r = 0.05 is the decimal form of 5%
t = 2 years

We will plug these three pieces of info into the formula to get...
A = P*(1+r)^t
A = 280*(1+0.05)^2
A = 280*(1.05)^2
A = 280*(1.1025)
A = 308.70

Answer: 308.70 dollars
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3 years ago
18n squared + 57n -10
aniked [119]
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way

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-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.

so (n-3)(n+60)
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do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u>   18   10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"

=(18n-3)(10n-3)

therefore your answer is (18n-3)(10n-3)
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