The area of the largest triangle would be 6 inches².
How did I get this? I'll explain first:
We would want our triangle to have the longest sides, so it can be big. If you think of a rectangle, a triangle can fit into it if:
The base (bottom) of the triangle is the same length as one side of the rectangle, and the other side of the triangle is perpendicular (90°) to the bottom and is the same length of the other side of the rectangle.
Okay, just picture it: two sides of the triangle are resting in the two sides of the rectangle, and the third side of the triangle is a line that splits the rectangle in half from one corner to the other.
I've added an image to explain.
The formula to find the area of a triangle is half of the base × height.
A of Δ = half of 3 × 4A = 1.5 × 4 = 6 inches²!
The correct is 44 because you estamate and 48 is close to 44
I’m pretty sure the answer is u<19
Answer:
x =12
Step-by-step explanation:
We can use the Pythagorean theorem to solve for x
a^2 + b^2 = c^2
16^2 + x^2 = 20^2
256 +x^2 = 400
Subtract 256 from each side
256-256 +x^2 = 400-256
x^2 =144
Take the square root of each side
sqrt(x^2) =sqrt(144)
x = 12
Answer:
If PQRS is a parallelogram with two adjacent congruent sides, then it must be a rhombus. A rhombus is a parallelogram characterized by having all sides congruent. Therefore, the adjacent sides must be congruent as well.