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alexandr1967 [171]
3 years ago
12

Each of n specimens is to be weighed twice on the same scale. Let Xi and Yi denote the two observed weights for the ith specimen

. Suppose Xi and Yi are independent of each other, each normally distributed with mean value μi (the true weight of specimen i) and variance Ï2.
a. Show that the maximum likelihood estimator of Ï2 is Xi and Yi.
Mathematics
1 answer:
Setler [38]3 years ago
8 0

Answer:

attached below

Step-by-step explanation:

Attached below is a detailed solution to your problem above

a) show that the maximum likelihood estimator of Ï2 is Xi and Yi.

attached below is the detailed solution

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Can someone ask me about this, which is algebra, please
krok68 [10]

Answer:

The correct answer is not shown in your picture. You must get a = 60.

Step-by-step explanation:

(1/2)a + (2/3)b = 50

b = 30

(1/2)a + (2/3)(30) = 50

(1/2)a + 20 = 50

(1/2)a + 20 - 20 = 50 - 20

(1/2)a = 30

2 * (1/2)a = 2 * 30

a = 60

The correct answer is not shown in your picture. You must get a = 60.

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A cyclist at a grocery store, 180m from his home decides to go to the post office which is 510m from his home in the same direct
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A) -180m
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Can someone help me?
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Answer:

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Step-by-step explanation:

Take the root of both sides and solve.

j=5√80vπ⁴/2π

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2 years ago
I need help with this question
Lelechka [254]

Answer:

c

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Let X denote the number of bars of service on your cell phone whenever you are at an intersection with the following probabiliti
ZanzabumX [31]

Answer:

a. P(2 \leq X \leq 3) = 0.5

b. P(X \geq 1) = 0.9

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d. P(X > 3) = 0.25

Step-by-step explanation:

We are given the following distribution:

P(X = 0) = 0.1

P(X = 1) = 0.15

P(X = 2) = 0.25

P(X = 3) = 0.25

P(X = 4) = 0.15

P(X = 5) = 0.1

a. Two or three bars

P(2 \leq X \leq 3) = P(X = 2) + P(X = 3) = 0.25 + 0.25 = 0.5

Thus:

P(2 \leq X \leq 3) = 0.5

b. At least one bar

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1 = 0.9

Thus:

P(X \geq 1) = 0.9

c. Fewer than two bars

P(X < 2) = P(X = 0) + P(X = 1) = 0.1 + 0.15 = 0.25

Thus:

P(X < 2) = 0.25

d. More than three bars

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Thus:

P(X > 3) = 0.25

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3 years ago
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