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alexandr1967 [171]
3 years ago
12

Each of n specimens is to be weighed twice on the same scale. Let Xi and Yi denote the two observed weights for the ith specimen

. Suppose Xi and Yi are independent of each other, each normally distributed with mean value μi (the true weight of specimen i) and variance Ï2.
a. Show that the maximum likelihood estimator of Ï2 is Xi and Yi.
Mathematics
1 answer:
Setler [38]3 years ago
8 0

Answer:

attached below

Step-by-step explanation:

Attached below is a detailed solution to your problem above

a) show that the maximum likelihood estimator of Ï2 is Xi and Yi.

attached below is the detailed solution

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The area of another rectangle is x² + 5x + 6. If one side measures (x + 2), what is the measure of the other
tiny-mole [99]
  • L=x+2
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\\ \sf\longmapsto LB=Area

\\ \sf\longmapsto B(x+2)=x^2+5x+6

\\ \sf\longmapsto B(x+2)=(x+2)(x+3)

  • Cancel x+2

\\ \sf\longmapsto B=x+3

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Find last​ year's salary​ if, after a 4 % pay​ raise, this​ year's salary is $ 33,280.
son4ous [18]

Answer: 31,948.80

Step-by-step explanation: I thin it his is correct. I multiplied the original amount by .04 then subtracted that from the original number.

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3 years ago
These equations represent the number of bacteria in four different dishes as a function of time, t, in days. Which equation repr
bagirrra123 [75]

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   ⇒ <em>is the </em><u><em>base in the exponent</em></u><em>:</em>

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<em />

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7 0
2 years ago
Simplify the expression 5^3 x 5^-5
kotykmax [81]

Answer:

\frac{1}{5^2} --- 1 over 5 squared

Step-by-step explanation:

When multiplying terms with a common base, you just add the exponents:

x^a\times x^b=x^{a+ b}

That's true even when you don't have any exponents.

5\times5=5^1\times5^1=5^{1+1}=5^2=25

\rightarrow5^3\times5^{-5}\\\rightarrow5^{3-5}\\\rightarrow5^{-2}

A negative exponent isn't fully simplified, so there's another rule to use:

x^{-y}=\frac{1}{x^y}

That is '1 over x to the y' if it's too small to read.

\rightarrow5^{-2}=\frac{1}{5^2}

4 0
2 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST<br> -SEE ATTACHMENT-
yuradex [85]

ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

The coefficients are :

1, 5, 10,10, 5,1

Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
4 years ago
Read 2 more answers
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