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Nastasia [14]
3 years ago
15

write a linear equation in slope-intercept form with a slope of -5 and passes through the point (-1,8)

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

y=-5x-13

Step-by-step explanation:

use y-y1=m(x-x1)

y+8=-5(x+1)

y+8=-5x-5

subtract 8 from both sides

y=-5x-13

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Solve the following equations | 3x + 3/7 | = 2 1/3
jasenka [17]

Answer:

X∈\frac{5}{63}, -\frac{23}{63}

Step-by-step explanation:

7 0
3 years ago
A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe
djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

\mathbf{h(t) = -16t^2 + 160t}

Differentiate the function with respect to t

\mathbf{h'(t) = -32t + 160}

Set to 0

\mathbf{h'(t) = -32t + 160 = 0}

So, we have:

\mathbf{-32t + 160 = 0}

Collect like terms

\mathbf{-32t =- 160 + 0}

\mathbf{-32t =- 160}

Solve for t

\mathbf{t = \frac{- 160}{-32}}

\mathbf{t = 5}

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0
3 years ago
What is 2,345 rounded to the nearest 10
ser-zykov [4K]
2,350 Hope this helped
8 0
4 years ago
Read 2 more answers
Why does -2(x + 3y) = 18 equal y=-3-x/3? Please helppp
Citrus2011 [14]

Step-by-step explanation:

You're asking why

{- 2(x + 3y) = 18} = y =  - 3 -  \frac{x}{3}

let's transpose the first equation for y

-2x-6y=18

-6y=18+2x

6y=-18-2x

y=-18/6-2x/6

y=-3-⅓x as required

8 0
3 years ago
Read 2 more answers
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
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