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Sergio039 [100]
3 years ago
7

What is the distance between -a and a 100 points if you mark asap

Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Answer:

-a is the good and a is the ordinary distances

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Write the expression in factored form. 81m^2-49
ivolga24 [154]
We can use the difference of two squares, which is:

x^2 + y^2 = (x-y)(x+y)

So,

(9m-7)(9m+7)

Hope this helps!
5 0
3 years ago
Hello guys can you help me with this?​
Katyanochek1 [597]

Answer:

Step-by-step explanation:

1. Title of the graph → Comparison of the Plant Growth

2. y-axis represents the height of the plants in centimeters.

3. On day 2:

   Height of plant A (plant outside) = 5.1 cm

   Height of plant B (plant near the window) = 2.25 cm

4. Plant outside shows great increase in the height.

    On day 5,

    Height of the plant outside = 6.75 cm

    Growth in height from day 2 to day 5 = 6.75 - 5.1

                                                                   = 1.65 cm

    Height of the plant near the window = 2.5 cm

    Growth in height of the plant from day 2 to day 5 = 2.5 - 2.25

                                                                                        = 0.25 cm

    Therefore, plant outside shows the great increase in height.

5. Plant near the window grew 0.25 cm in height.

4 0
3 years ago
A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. compute the probability o
Hunter-Best [27]
10C9 * (1/5)^9 * (4/5)^1 = 4.096*10^-6

About 4 chances in 1 million.
8 0
3 years ago
What is the midpoint of EC ?
sergij07 [2.7K]

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

7 0
3 years ago
If f(x, y)=xy−x^2, what is the value of f(f(−2, 3), −4)? Explain your reasoning.
hjlf

\bf f(x,y)=xy-x^2 \\\\[-0.35em] ~\dotfill\\\\ f(\stackrel{x}{-2},\stackrel{y}{3})=(-2)(3)-(-2)^2\implies f(-2,3)=-6-(4)\implies f(-2,3)=-10 \\\\[-0.35em] ~\dotfill\\\\ f(~~\underline{f(-2,3)},~~-4)\implies f(\stackrel{x}{\underline{-10}},\stackrel{y}{-4})=(-10)(-4)-(-10)^2 \\\\\\ f(-10,-4)=40-(100)\implies f(-10,-4)=-60

3 0
3 years ago
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