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igomit [66]
3 years ago
14

1

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Moving up would add to the Y value. Moving to the left subtracts from the X value.

The answer would be: (X,Y) — (x-3, y + 5)

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Suppose M is the midpoint of line FG.
alukav5142 [94]
A)\\|FM|=5y+13;\ |MG|=5-3y\\\\|FG|=|FM|+|MG|\\\\|FG|=(5y+13)+(5-3y)=2y+18\\\\B)\\|FM|=8a+1;\ |FG|=42\\\\|FG|=2|FM|\\\\2(8a+1)=42\\16a+2=42\ \ \ \ \ |subtract\ 2\  from\ both\ sides\\16=40\ \ \ \ \ |divide\ both\ sides\ by\ 16\\a=\frac{40}{16}\\a=\frac{5}{2}\\a=2.5

6 0
3 years ago
-3x - 4y = 2<br> 3x + 3y = -3
densk [106]

Answer:

x = -2

y = 1

Step-by-step explanation:

-3x - 4y = 2

x = -2

y = 1

3x + 3y = -3

x = -2

y = 1

5 0
3 years ago
Ann is mailing packages. Each small package costs her $2.10 to send. Each large package costs her $3.30. How much will it cost h
Liula [17]

Answer:

$35.76

Step-by-step explanation:

12.60

23.10

--------

35.76

4 0
3 years ago
Read 2 more answers
It is known that a cable with a​ cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the
vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its​ cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0
3 years ago
Read 2 more answers
Solve the following equation for y: 2x-3y=6
Minchanka [31]

2x-3y=6

-y=6

y=-6

<u>Check your Work</u>

-6(2) - 3(-6)=

-12-(-18)=

-12+18=6

5 0
3 years ago
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