The ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches. Solve for the perim
2 answers:
You might be interested in
Answer:
5
Step-by-step explanation:
for the first gear
revolutions/teeth
1 / 24
2 / 48
3 / 72
4 / 96
5 / 120
6 / 144
for the second gear
revolutions/teeth
1 / 40
2 / 80
3 / 120
4 / 160
<em>the two marks will meet after 120 teeth, 5 revolutions of the first gear and 3 revolutions of the second.</em>
the way to get that amount of teeth is
the Least Common Multiple equals the product of all factors, but those factors who are repeted for both numbers should be only once.
120 teeth are 5 revolutions for gear1 and 3 por gear2
Answer:
a. $1.03
b. $0.93
c. 0.98
d. 2 workers
Step-by-step explanation:
a. Given that:
- 1 computer : 1 worker : inventory 150 items per hour
- 1 computer : 2 workers : inventory 200 items per hour
- 1 computer : 3 workers : inventory 220 items per hour
- 1 computer : 4+ workers : fewer than 235 items per hour
- Cost: $100 per computer ; $25 per worker
The fixed production factor in the warehouse is the computer used:
-One computer used, but the number of users is varied to inventory a specified number of items.
-The variable production factor is the number of workers assigned per one computer.
#The cost of inventorying a single item by one worker is:
Hence, the cost of inventorying a single item is $1.03
b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :
Hence, the cost of inventorying a single item is $0.93
c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :
Hence, the cost of inventorying a single item is $0.98
d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.
Take any number less than 235(say 234) as the inventory units:
From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.