Each curve completes one loop over the interval

. Find the intersections of the curves within this interval.

The region of interest has an area given by the double integral

equivalent to the single integral

which evaluates to

.
Answer:
3 peices left over
Step-by-step explanation:
4x10=40
40+5=45
45/6=7.5
7x6=42
45-42=3
Answer:
Step-by-step explanation:
f(x) = 1/2(4)^x
Plug in 3 for x
f(3) = 1/2(4)³
Cube 4.
4³ = 4 x 4 x 4 = 64
f(3) = 1/2(64)
Multiply 64 with 1/2 (or divide by 2)
f(3) = 64/2
f(3) = 32